Shashank Shekher
Shashank Shekher

Reputation: 897

Bash flatten an array to key value pair

I have an array mentioned below.

Array

wf.example.input1=/path/to/file1 
wf.example.input2=/path/to/file2 
wf.example.input3=["/path/to/file3","/path/to/file4"]

declare -p Array gives me below output.

([0]="wf.example.input1=/path/to/file1" [1]="wf.example.input2=/path/to/file2" [2]="wf.example.input3=[\"/path/to/file3\",\"/path/to/file4\"]")

I need to flatten this array ib bash script and give me output like below.

Output

name:"wf.example.input1", value:"/path/to/file1"
name:"wf.example.input2", value:"/path/to/file2"
name:"wf.example.input3", value:"/path/to/file3"
name:"wf.example.input3", value:"/path/to/file4"

Upvotes: 0

Views: 764

Answers (1)

anubhava
anubhava

Reputation: 785701

Using printf piped to awk to get formatting:

declare -a arr='([0]="wf.example.input1=/path/to/file1"
[1]="wf.example.input2=/path/to/file2"
[2]="wf.example.input3=[\"/path/to/file3\",\"/path/to/file4\"]")'

printf "%s\n" "${arr[@]}" |
awk -F= '{
   n=split($2, a, /,/)
   for (i=1; i<=n; i++) {
      gsub(/^[^"]*"|"[^"]*$/, "", a[i])
      printf "name:\"%s\", value:\"%s\"\n", $1, a[i]
   }
}'

Output:

name:"wf.example.input1", value:"/path/to/file1"
name:"wf.example.input2", value:"/path/to/file2"
name:"wf.example.input3", value:"/path/to/file3"
name:"wf.example.input3", value:"/path/to/file4"

Upvotes: 3

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