CODEWITHSUNDEEP
pythonstring
user7576140
user7576140

Reputation:

Spilt a string and appending

I have a string for example:

"112233445566778899"

How can I spilt it to the following pattern:

"\x11\x22\x33\x44\x55\x66\x77\x88\x99"

I could spilt the string with following commands, but I could find out a way to append "\x" to the them:

s = "112233445566778899"
[s[i:i + 2] for i in range(0, len(s), 2)]

Upvotes: 0

Views: 147

Answers (4)

Vibhutha Kumarage
Vibhutha Kumarage

Reputation: 1399

I think using regular expressions can you the best. Because it can find doubled characters anywhere on the string.

>>>import re
>>>string = "112233445566778899" 
>>>x = ''.join(r'\x{}'.format(s) for s in re.finditer(r'(\w)\1',string))
>>>x
'\\x11\\x22\\x33\\x44\\x55\\x66\\x77\\x88\\x99'
>>> print(x)
\x11\x22\x33\x44\x55\x66\x77\x88\x99

Upvotes: 0

Killer Death
Killer Death

Reputation: 459

s = "112233445566778899"
a = [r'\x' + s[i:i + 2] for i in range(0, len(s), 2)]
print(''.join(a))

Upvotes: 0

Chris
Chris

Reputation: 22953

Assuming your string will always have an even length, you always want to split the string into pairs, and that your string is already ordered:

>>> string = "112233445566778899"
>>> joined = ''.join(r'\x{}'.format(s + s) for s in string[1::2])
>>> print(joined)
\x11\x22\x33\x44\x55\x66\x77\x88\x99
>>>

Upvotes: 1

Bubble Hacker
Bubble Hacker

Reputation: 6723

You can do the following edit to your code:

...
[r"\x"+s[i:i + 2] for i in range(0, len(s), 2)]
...

Notice that this will return two forward slashes:

['\\x11', '\\x22', '\\x33', '\\x44', '\\x55', '\\x66', '\\x77', '\\x88', '\\x99']

This is because of Python escaping the \ using the escaping character \.

When using the string you will notice that one of the \ disappears:

>> x = ['\\x11', '\\x22', '\\x33', '\\x44', '\\x55', '\\x66', '\\x77', '\\x88', '\\x99']
>> print(x[0])
>> '\x11'

Upvotes: 0

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