CODEWITHSUNDEEP
pythonsocketsapache-sparkpysparkspark-streaming
fcgtyg
fcgtyg

Reputation: 51

Spark Streaming App can not receive strings on a port

I want to write a Spark Streamin App which takes a stream with random integers and count them. Here is the Spark app I wrote:

from pyspark import SparkContext
from pyspark.streaming import StreamingContext

sc = SparkContext("local[2]", "IntegerCount") # 2 threads, app name
ssc = StreamingContext(sc, 1) # sc, time interval for batch update.

nums = ssc.socketTextStream("localhost", 8000) # stream data from TCP; source, port

# create key,value pairs
tests = nums.map(lambda num: (int(num), 1))

# Count each integer in each batch
intCounts = tests.reduceByKey(lambda x, y: x + y)

# Print
intCounts.pprint()

ssc.start()             # Start the computation
ssc.awaitTermination()  # Wait for the computation to terminate

And I am serving random numbers to port 8000 with that Server.py:

import socket
from random import randint

host = 'localhost'
port = 8000
address = (host, port)

server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.bind(address)
server_socket.listen(5)


print "Listening for client . . ."
conn, address = server_socket.accept()
print "Connected to client at ", address
#pick a large output buffer size because i dont necessarily know how big the incoming packet is
while True:
    output = str(randint(0, 10))
    conn.send(output)

When I run the Server.py and my Spark App, connection establishes succesfully. However I see an empty output which is that:

Using Spark's default log4j profile: org/apache/spark/log4j-defaults.properties
Setting default log level to "WARN".
To adjust logging level use sc.setLogLevel(newLevel). For SparkR, use setLogLevel(newLevel).
-------------------------------------------
Time: 2017-07-16 22:36:11
-------------------------------------------

-------------------------------------------
Time: 2017-07-16 22:36:12
-------------------------------------------

I don't know what is the problem, please help me to make understand what is going on?

Upvotes: 2

Views: 910

Answers (1)

fcgtyg
fcgtyg

Reputation: 51

Solved, I sent strings with "\n" and it worked.

import socket
from random import randint

host = 'localhost'
port = 8000
address = (host, port)

server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server_socket.bind(address)
server_socket.listen(5)


print "Listening for client . . ."
conn, address = server_socket.accept()
print "Connected to client at ", address
#pick a large output buffer size because i dont necessarily know how big the incoming packet is
while True:
    output = str(randint(0, 10)) + "\n"  ### THAT IS THE FIX.
    conn.send(output)

Upvotes: 3

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