CODEWITHSUNDEEP
php
Tom Chambers
Tom Chambers

Reputation: 71

HOw to make this php class work as expected

Can anyone see what i have done incorreclty using this class it should change the word before to after but it just sits there doing nothing. The second php pgm is the actual classs I am using..

<?php

include("parse.inc.php");

$bob = new parseClass();

$tag = "{Before}";
$replacement = "After";
$content = "My animal runs around all over the place and his name is {Before}.";
$bob->ReplaceTag($tag, $replacement, $content);
echo $bob;

?>




parse.inc.php (file name)
***************************

<?php
Class parseClass {

    function ReplaceTag($tag, $replacement, $content) {
        $content = str_replace($tag, $replacement, $content);
        return $content;
    }

}

// END Class parseClass
?>

Upvotes: 0

Views: 105

Answers (5)

user3610879
user3610879

Reputation: 1

Simply replace these two lines

$bob->ReplaceTag($tag, $replacement, $content);

echo $bob;

with

$content = $bob->ReplaceTag($tag, $replacement, $content);

echo $content;

Upvotes: 0

localheinz
localheinz

Reputation: 9592

If the hard requirement is that you want to be able to echo the instance of parseClass, try this:

class parseClass 
{
    private $content;

    public function ReplaceTag($tag, $replacement, $content) 
    {
        $this->content = str_replace($tag, $replacement, $content);
    }

    public function __toString()
    {
        return $this->content;
    }
}

$bob = new parseClass();

$tag = "{Before}";
$replacement = "After";
$content = "My animal runs around all over the place and his name is {Before}.";

$bob->ReplaceTag($tag, $replacement, $content);

echo $bob;

For reference, see:

Upvotes: 0

Liu.handy
Liu.handy

Reputation: 59

I guess you want to print the string having be replaced,so you should :

$result = $bob->ReplaceTag($tag, $replacement, $content);
echo $result;

Why are you use echo to print class?If you want to do this,please use "var_dump" or 'print_r' instead;

Upvotes: 0

JimmyLOL
JimmyLOL

Reputation: 47

In your case, you pass the content into class's function Therefore, you should store the return value into variable first

$result = $bob->ReplaceTag($tag, $replacement, $content);

echo $result;

Upvotes: 1

djt
djt

Reputation: 7535

You just need to store the result of your function in a local variable, and print that. 

$result = $bob->ReplaceTag($x, $y, $z);
print($result);

Upvotes: 0

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