CODEWITHSUNDEEP
javadateparsingdatetimezoneddatetime
Akiner Alkan
Akiner Alkan

Reputation: 6862

ZonedDateTime parse exception

I am trying to convert string to ZonedDateTime.

I have tried following:

SimpleDateFormat zonedDateTimeFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS Z");   
zonedDateTimeFormat.setTimeZone(TimeZone.getTimeZone("GMT")); 

long timeMs = zonedDateTimeFormat.parse("2017-07-18T20:26:28.582+03:00[Asia/Istanbul]").getTime();

It gives java.text.ParseException: Unparseable date

How can I parse the following string into ZonedDateTime

2017-07-18T20:26:28.582+03:00[Asia/Istanbul]

Upvotes: 2

Views: 2755

Answers (4)

Arvind Kumar Avinash
Arvind Kumar Avinash

Reputation: 78935

Do not pollute the clean, java.time API with the error-prone, java.util and java.text date-time API

In March 2014, Java 8 introduced the modern, java.time date-time API which supplanted the error-prone legacy, java.util and java.text date-time API. Any new code should use the java.time API*.

Solution using modern date-time API

Given below is the excerpt from ZonedDateTime#parse documentation:

Obtains an instance of ZonedDateTime from a text string such as 2007-12-03T10:15:30+01:00[Europe/Paris]. The string must represent a valid date-time and is parsed using DateTimeFormatter.ISO_ZONED_DATE_TIME.

Since your text string, 2017-07-18T20:26:28.582+03:00[Asia/Istanbul] fully complies with the default format, you do not need to specify any DateTimeFormatter explicitly.

Demo:

public class Main {
    public static void main(String[] args) {
        ZonedDateTime zdt = ZonedDateTime.parse("2017-07-18T20:26:28.582+03:00[Asia/Istanbul]");
        System.out.println(zdt);
    }
}

Output:

2017-07-18T20:26:28.582+03:00[Asia/Istanbul]

Online Demo

Learn more about the modern Date-Time API from Trail: Date Time.

If you are receiving an instance of java.util.Date, convert it tojava.time.Instant, using Date#toInstant and derive other date-time classes of java.time from it as per your requirement.

Upvotes: 2

Anton Balaniuc
Anton Balaniuc

Reputation: 11739

For ZonedDateTime we need to use ZonedDateTime.parse method with DateTimeFormatter. If I am not wrong you have an ISO date:

 ZonedDateTime zonedDateTime = ZonedDateTime.parse(
         "2017-07-18T20:26:28.582+03:00[Asia/Istanbul]",
         DateTimeFormatter.ISO_DATE_TIME
 );
 System.out.println(zonedDateTime); //2017-07-18T20:26:28.582+03:00[Asia/Istanbul]

You can use either ISO_ZONED_DATE_TIME or ISO_DATE_TIME. Both are able to parse a date-time with offset and zone.

Upvotes: 2

Pallavi Sonal
Pallavi Sonal

Reputation: 3881

The java.time API has many inbuilt-formats that simplify parsing and formatting process. The String you are trying to parse is in the standard ISO_ZONED_DATE_TIME format. So, you could parse it easily in the following way and then get the milliseconds from the epoch:

DateTimeFormatter formatter = DateTimeFormatter.ISO_ZONED_DATE_TIME ;
ZonedDateTime zdt = ZonedDateTime.parse(
                        "2017-07-18T20:26:28.582+03:00[Asia/Istanbul]", 
                        formatter);  // prints 2017-07-18T20:26:28.582+03:00[Asia/Istanbul]
long timeInMs = zdt.toInstant().toEpochMilli();

Upvotes: 3

Kiskae
Kiskae

Reputation: 25573

ZonedDateTime.parse seems to be designed to handle the exact string you provided. There is no need to go through the old SimpleDateFormat

Upvotes: 2

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