CODEWITHSUNDEEP
c++c++11
Jaden
Jaden

Reputation: 105

How " return {...}; " works in C++11?

I'm trying to implement a String. I want to convert the String to lower case, so called boost::to_lower_copy(m_s). In fact, m_s is of type std::string. My question is how return {boost::to_lower_copy(m_s)}; works in function to_lower_copy(). How could it return a String type? Thanks a lot.

class String {
    std::string m_s;
public:
    String(const std::string s) : m_s(s) { }
    String to_lower_copy() const {
        return {boost::to_lower_copy(m_s)};
    }
};

Upvotes: 0

Views: 168

Answers (1)

eerorika
eerorika

Reputation: 238311

attr(optional) return braced-init-list ; is alternative return statement syntax introduced in C++11. It copy-list-initializes the return value of the function. The compiler knows the type that the function returns, because it is part of the declaration.

Upvotes: 1

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