CODEWITHSUNDEEP
python
JamesHudson81
JamesHudson81

Reputation: 2273

check if the function works inside another function

I have the following functions:

def outer_function():
    return 'It worked'

def fun():
    try:
        return function1()
    except:
        return function2()

When executing fun()I would like to check that if function1() works correctly, then fun() can return an array such as this 

[function1(),outer_function()]

How could I check whether function1() works inside ´fun() and return an output such as the desired one?

Upvotes: 1

Views: 98

Answers (3)

victor
victor

Reputation: 1644

Instead of return function1(), do return [function1(), outer_function()]

So your function would be:

def fun():
    try:
        return [function1(), outer_function()]
    except:
        return function2()

If function1() raises an error, the array will NOT be returned. Instead, the try block will catch the Exception.

NOTE: This code is contingent on the fact that function2 and outer_function will not raise any errors of their own.

Upvotes: 1

Akshay
Akshay

Reputation: 373

I have tried your question and made it on 'Repl.it' Online Compiler. Here Your Link

def function1():
  try:
    return True
  except :
    return False

def function2():
  try:
    return True
  except:
    return False

def outer_function():
  return 'It worked'

def fun():
  if function1():
    return [function1(), outer_function()]
  else:
    return function2()

print(fun())

Upvotes: 0

Cary Shindell
Cary Shindell

Reputation: 1386

You can create a variable for function1 output, and if function1 throws an error it will stop the return statement and go into the catch/except. Otherwise it will go to the else statement and return the desired array:

def outer_function():
return 'It worked'

def fun():
    try:
        x = function1()
    except:
        return function2()
    else:
        return [x, outer_function()]

Upvotes: 2

Related Questions