CODEWITHSUNDEEP
phparraysforeach
Fabian Amran
Fabian Amran

Reputation: 1311

Getting error when echoing out an array key outside of foreach loop

Why is it that when I setup an array like this:

$plans[] = array(
  'provider'  => 'Boost Mobile',
  'plan'   => 'Unlimited Gigs',
   'url'  => 'https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/',
  'price'      => 50,
  'duration' => 'month',
}

I get an arror if I echo out a key like this:

echo $plans['plan'];

//Notice: Undefined index: plan

BUT when I echo it out inside a foreach array it outputs the value?

Any help is appreciated

Upvotes: 0

Views: 97

Answers (5)

Wael Assaf
Wael Assaf

Reputation: 1303

You are actually just adding another element (which is, in this case, an array) to an existing array called $plans if you want to define an array $plans use this

$plans = array(
  'provider'  => 'Boost Mobile',
  'plan'   => 'Unlimited Gigs',
   'url'  => 'https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/',
  'price'      => 50,
  'duration' => 'month',
}

So now you can retrieve the value of the key 'plan' from your $plans array with this line

echo $plans['plan'];

Upvotes: 1

RJParikh
RJParikh

Reputation: 4166

You have define $plan with array so no need to take [] with $plans because it create multi dimentional array.

I have added both example with and without [].

Note

$plans[] = array(); // It creates multi dimensional array
$plans = array(); // It creates simple array

Code

<?php

$plans[] = array(
  'provider'  => 'Boost Mobile',
  'plan'   => 'Unlimited Gigs',
   'url'  => 'https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/',
  'price'      => 50,
  'duration' => 'month');

print_r($plans);
echo $plans[0]['plan']; echo "\n\n";

$plans2 = array(
  'provider'  => 'Boost Mobile',
  'plan'   => 'Unlimited Gigs',
   'url'  => 'https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/',
  'price'      => 50,
  'duration' => 'month');

print_r($plans2);
echo $plans2['plan'];

Output

Array
(
    [0] => Array
        (
            [provider] => Boost Mobile
            [plan] => Unlimited Gigs
            [url] => https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/
            [price] => 50
            [duration] => month
        )

)

Unlimited Gigs

Array
(
    [provider] => Boost Mobile
    [plan] => Unlimited Gigs
    [url] => https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/
    [price] => 50
    [duration] => month
)

Unlimited Gigs

Check Demo : Click Here

Upvotes: 1

Milan Chheda
Milan Chheda

Reputation: 8249

$plans is a two-dimensional array. If you want to show plan, you need to use give the first dimension too, which is 0 in your case. 

print_r($plans);
Array
(
    [0] => Array
        (
            [provider] => Boost Mobile
            [plan] => Unlimited Gigs
            [url] => https://www.boostmobile.com/#!/shop/plans/monthly-phone-plans/
            [price] => 50
            [duration] => month
        )

)

And here is what echo would give you: 

echo $plans[0]['plan'];
Unlimited Gigs

Click here for demo: https://3v4l.org/Ytk79

Upvotes: 1

Arun Kumaresh
Arun Kumaresh

Reputation: 6311

if it is $plans[] then you should do this

echo $plans[0]['plan'];

if it is $plans then it will be 

echo $plans['plan'];

Upvotes: 0

Gyandeep Sharma
Gyandeep Sharma

Reputation: 2327

You are adding an array at $plans[0].

So your value is as follows.

  $plans[0]['plan'];

You can view full array by this

echo "<pre>"; print_r($plans);

Upvotes: 0

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