CODEWITHSUNDEEP
javaregexstring
Vijay Manohar
Vijay Manohar

Reputation: 493

Splitting String based on nth Occurence of a String in Java

How to Split a String based on the nth(Ex: second) occurence of a delimiter.whereas other than the nth occurence ,all other delimiters should be retained

I/P:

 String name="This is my First Line";
 int delimiter=" ";
 int count=3;//This is a dynamic value

O/P:

String firstpart=This is my
String Secondpart=First Line

Upvotes: 2

Views: 3509

Answers (5)

Technocraft Studio
Technocraft Studio

Reputation: 1

Simply like this, Tested and work perfectly in Java 8

public String[] split(String input,int at){
    String[] out = new String[2];
    String p = String.format("((?:[^/]*/){%s}[^/]*)/(.*)",at);
    Pattern pat = Pattern.compile(p);
    Matcher matcher = pat.matcher(input);
       if (matcher.matches()) {
          out[0] = matcher.group(1);// left
          out[1] = matcher.group(2);// right
       }
    return out;
} 

//Ex: D:/folder1/folder2/folder3/file1.txt
//if at = 2, group(1) = D:/folder1/folder2  and group(2) = folder3/file1.txt

Upvotes: -1

daniu
daniu

Reputation: 14999

static class FindNthOccurrence
{
    String delimiter;

    public FindNthOccurrence(String del)
    {
        this.delimiter = del;
    }

    public int findAfter(String findIn, int findOccurence)
    {
        int findIndex = 0;
        for (int i = 0; i < findOccurence; i++)
        {
            findIndex = findIn.indexOf(delimiter, findIndex);
            if (findIndex == -1)
            {
                return -1;
            }
        }
        return findIndex;
    }
}

FindNthOccurrence nth = new FindNthOccurrence(" ");
String string = "This is my First Line";
int index = nth.nthOccurrence(string, 2);
String firstPart = string.substring(0, index);
String secondPart = string.substring(index+1);

Upvotes: 0

Bohemian
Bohemian

Reputation: 424983

Due to limitations with regex, you can't split it in 1 line of code, but you can do it in 2 lines:

String firstPart = name.replaceAll("^((.*?" + delimiter + "){" + count + "}).*", "$1");
String secondPart = name.replaceAll("^(.*?" + delimiter + "){" + count + "}(.*)", "$2");

Upvotes: 5

Zabuzard
Zabuzard

Reputation: 25903

Just use indexOf to search for the delimiter and repeat that until you found it count-times. Here is a snippet:

String name = "This is my First Line";
String delimiter = " ";
int count = 3;

// Repeativly search for the delimiter
int lastIndex = -1;
for (int i = 0; i < count; i++) {
    // Begin to search from the position after the last matching index
    lastIndex = name.indexOf(delimiter, lastIndex + 1);

    // Could not be found
    if (lastIndex == -1) {
        break;
    }
}

// Get the result
if (lastIndex == -1) {
    System.out.println("Not found!");
} else {
    // Use the index to split
    String before = name.substring(0, lastIndex);
    String after = name.substring(lastIndex);

    // Print the results
    System.out.println(before);
    System.out.println(after);
}

It will now output

This is my
 First Line

Note the whitespace (the delimiter) at the beginning of the last line, you can omit this if you want by using the following code at the end

// Remove the delimiter from the beginning of 'after'
String after = ...
after = after.subString(delimiter.length());

Upvotes: 1

Karthik Tsaliki
Karthik Tsaliki

Reputation: 196

I got it like this

String name="This is my First Line";

 int count=3;

 String s1,s2;

 String arr[]=name.split();//default will be space

 for(i=0;i<arr.length;i++)

   if(i<count)

    s1=s1+arr[i]+" "

   else 

    s2=s2+arr[i]+" "

Upvotes: 1

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