CODEWITHSUNDEEP
phparrays
jumpman8947
jumpman8947

Reputation: 581

php array offset 0, when 0 exists

when i echo 

print_r(array_values(array_filter($exampleArray[5]["Numbers"])));

I get an array which looks like 

Array ( [0] => 100 
        [1] => 31 
        [2] => 023 )

But when i echo the statement

print_r(array_values(array_filter($exampleArray[5]["Numbers"][0])));

I get 

Notice: Undefined offset: 0 
Warning: array_filter() expects parameter 1 to be array, null given
Warning: array_values() expects parameter 1 to be array, null given

messages. Clearly there is a 0 index but i don't know why i'm getting errors.

Upvotes: 0

Views: 125

Answers (1)

user3677687
user3677687

Reputation:

Simple As that $exampleArray[5]["Numbers"][0] is not an array rather it is a String.

If you want to get the index[0] value you should call index 0 on array_values response

print_r(array_values(array_filter($exampleArray[5]["Numbers"]))[0]);

The above code will return 100

Upvotes: 2

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