CODEWITHSUNDEEP
phpjqueryjson
user3675220
user3675220

Reputation: 81

Jquery post JSON to PHP

I'm trying to pass JSON data from jQuery to PHP so I can overwrite a JSON file. The problem I'm having is that I can't figure out how to tell if the PHP file is receiving my json that I am sending. I'm a bit of a novice..

I currently have this - it's not doing the trick and I'm a bit stuck. Any advice would be great. I am getting alert - 'Right' but nothing from PHP.

var testjson = [{
  "name": 1,
  "myArray": [{ 
    "0":"1",
    "2":"3"
  },{
    "1":"2",
    "3":"4"
  }],
  "friends":40  
}];

$.ajax({
  type: "POST",
  url: "php/write.php",
  data: testjson,
  dataType: "html",
  contentType : 'application/json; charset=utf-8'
}).done(function(data, status) {
  alert('Right');
}).fail(function(data, status) {
  alert("Wrong: " + status);
});

$value = json_decode($_POST);
print_r($value);

Upvotes: 0

Views: 89

Answers (2)

user3675220
user3675220

Reputation: 81

Got it.

Knew it was super simple. Thanks for your help!

$value = $_POST;
print_r($value);

Upvotes: 0

Dev
Dev

Reputation: 672

Use the below code

var testjson =[{"name":1,"myArray":[{"0":"1","2":"3"},
            {"1":"2","3":"4"}],"friends":40}];

var myString = JSON.stringify(testjson);

$.ajax({
    type: "POST",
    url: "write.php",
    data: myString,
    dataType: "html"
     }).done( function (data, status) {
    alert('Right');
})
.fail( function (data, status) {
    alert("Wrong: "+status);
});
});

And in php

$json = json_decode(file_get_contents("php://input"));
print_r($json);

Upvotes: 1

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