Reputation: 877
I would like to know if I am doing something wrong or it is not possible to post only part of view model using default model binder. Let's say I have a complex viewmodel that only small part it should be posted. I would like to achieve something like this:
public class ComplexViewModel
{
public object FirstNotPostedData { get; set; }
public object SecondNotPostedData { get; set; }
//......
public object NthNotPostedData { get; set; }
public InnerModelToPost InnerModelToPost { get; set; }
}
public class InnerModelToPost
{
public string FirstProperty { get; set; }
public string SecondProperty { get; set; }
public string ThirdProperty { get; set; }
}
In view I would like to display part of model and post the other part:
@model ComplexViewModel
@* DISPLAYING DATA *@
<form>
@Html.HiddenFor( m => m.InnerModelToPost.FirstProperty )
@Html.HiddenFor( m => m.InnerModelToPost.SecondProperty )
@Html.HiddenFor( m => m.InnerModelToPost.ThirdProperty )
<button type="submit">Submit button</button>
</form>
And then I would like to be able to pass this model to my controller in this way using default model binder:
public ActionResult GetOnlyImportantPartOfModel( InnerModelToPost innermodel)
{
//I'm getting empty model when I' doing like this
return View();
}
You may ask why not to pass entire model as parameter to this action method. So the answer is: code readablity. I store ComplexViewModel in session and I read it in first line of my action method. I would like to pass only this data that I want to update my model with.
Upvotes: 1
Views: 1052
Reputation:
Your need to use the Prefix
property of [Bind]
attribute to strip the InnerModelToPost
prefix from your form values.
public ActionResult GetOnlyImportantPartOfModel([Bind(Prefix = "InnerModelToPost")] InnerModelToPost innermodel)
{
....
}
Having said that, if your only using properties of InnerModelToPost
, then in your GET method, you can read the parent class (ComplexViewModel
) from Session
, but pass only the InnerModelToPost
property to the view
Upvotes: 5