CODEWITHSUNDEEP
jsonjq
Branko
Branko

Reputation: 951

How to display two values serially with jq?

I am straggling some time with jq to parse json file. I have to grab ID and Name in the same line so I can do some logic after.

{
"elements": [{
        "id": "e20a9cd8-8683-4986-b6c0-e5fbf51cbf7f",
        "name": "Mike",
        "components": [{
            "id": "15f959fc-6d2d-451a-a59e-430a05a1852c",
            "pid": "ZZZ1"
        }],
        "tenantIds": null,
        "productIds": null
    },
    {
        "id": "d892f2eb-d7f3-49f8-9176-2113351cccf8",
        "name": "Steve",
        "components": [{
            "id": "0c44c917-e0e5-4fa3-b87c-89f9ac0815b4",
            "pid": "XXX3"
        }],
        "tenantIds": null,
        "productIds": null
    }
]

}

With jq '{elements}[] | .[].id I am getting ID's but I can't find solution how to add appropriate name beside ID. I tried something like

{elements}[] | .[].id + " " + .[].name

and

{elements}[] | .[].id + .[].name

but it's not what I expected.

I want to get:

15f959fc-6d2d-451a-a59e-430a05a1852c Mike
d892f2eb-d7f3-49f8-9176-2113351cccf8 Steve

Any suggestion?

Thanks!

Upvotes: 1

Views: 83

Answers (1)

RomanPerekhrest
RomanPerekhrest

Reputation: 92884

Apply string concatenation:

jq '.elements[] | .id +" "+ .name' file

The output:

"e20a9cd8-8683-4986-b6c0-e5fbf51cbf7f Mike"
"d892f2eb-d7f3-49f8-9176-2113351cccf8 Steve"

To output without double quotes use -r (--raw-output) option:

jq '.elements[] | .id +" "+ .name' -r file
e20a9cd8-8683-4986-b6c0-e5fbf51cbf7f Mike
d892f2eb-d7f3-49f8-9176-2113351cccf8 Steve

Upvotes: 2

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