hydra123
hydra123

Reputation: 347

extract a string with single quotes between parenthesis and single quote

I have the following code :

  #include <iostream>
#include <regex>

using namespace std;

int main()
{
  string s;

      s = "server ('m1.labs.terad  ata.com') username ('us er5') password('user)5') dbname ('def\\ault')";

    regex re("(\'(.*?)\'\)");
    sregex_token_iterator i(s.begin(), s.end(), re, 1);
   sregex_token_iterator j;

    unsigned count = 0;
    while(i != j)
      {
        cout <<*i<< endl;
        count++;
        i++;
      }
    cout << "There were " << count << " tokens found." << endl;

  return 0;
}

the regex above is meant to extract everything between the single quotes.

But how can I make the regex so that it is able to extract escaped single quotes (example username (user''5) should be extracted as 'user'5'.

Thanks in advance. I really need help with this . Had been trying for so many days.

Example

'm1.labs.terad  ata.com'
'us er5'
'user)5'
'def\ault'

There were 4 tokens found. Please note that the single quote around the string should be there. Thanks in advance for help.

But now if my string is

 s = "server ('m1.labs.terad  ata.com') username ('us ''er5') password('user)5') dbname ('def\\ault')";

The output should be :

   'm1.labs.terad  ata.com'
    'us 'er5'   <<<<<<<<<<<<<<<<<<<
    'user)5'
    'def\ault'

Upvotes: 1

Views: 1275

Answers (2)

sehe
sehe

Reputation: 393457

But how can I make the regex so that it is able to extract escaped single quotes (example username (user''5) should be extracted as 'user'5'.

Ugh. Is that what you meant? I was right about X/Y problem then.

Note: What you describe is known as escaping special characters. Two common ways to escape special characters:

  1. repeat it (e.g. printf("100%%"); to print 100%)
  2. introduce it using another escape (usually backslash). E.g.

    std::cout << "Hello \"World\"" << std::endl;
    

    Or, one more intricate example:

    std::cout << "Newline is \\n" << std::endl;
    

Here you go: just add q >> char_(q) to accept repeated quotes as quote-escape:

auto quoted = [](char q) { 
    return lexeme[ q >> *(
              q >> char_(q)  // accept repeated quotes as quote-escape
            | '\\' >> char_  // accept backs-slash escape
            | char_ - q      // accept any other non-quote
         ) >> q]; };

Nothing else changes relative to tokenizing string , accepting everything between given set of characters in CPP

Live On Coliru

#include <iostream>
#include <boost/spirit/home/x3.hpp>
#include <boost/fusion/adapted/std_pair.hpp>
#include <map>

using Config = std::map<std::string, std::string>;
using Entry  = std::pair<std::string, std::string>;

namespace parser {
    using namespace boost::spirit::x3;

    template <typename T> auto as = [](auto p) { return rule<struct _, T> {} = p; };
    auto quoted = [](char q) { return lexeme[q >> *(q >> char_(q) | '\\' >> char_ | char_ - q) >> q]; };

    auto value  = quoted('\'') | quoted('"');
    auto key    = lexeme[+alpha];
    auto pair   = key >> '(' >> value >> ')';
    auto config = skip(space) [ *as<Entry>(pair) ];
}

Config parse_config(std::string const& cfg) {
    Config parsed;
    auto f = cfg.begin(), l = cfg.end();
    if (!parse(f, l, parser::config, parsed))
        throw std::invalid_argument("Parse failed at " + std::string(f,l));
    return parsed;
}

int main() {
    auto const text = "server ('m1.labs.teradata.com') username ('use'')r_*5') password('u\" er 5') dbname ('default')";
    Config cfg = parse_config(text);

    for (auto& setting : cfg)
        std::cout << "Key " << setting.first << " has value " << setting.second << "\n";
}

Prints

Key dbname has value default
Key password has value u" er 5
Key server has value m1.labs.teradata.com
Key username has value use')r_*5

Upvotes: 2

ubombi
ubombi

Reputation: 1174

You should look at look-around and conditional regexp.
And regex engine should be PCRE compatible. (I don't know about C++)

You should newer use regexp, you have found in the internet if you dont understand it.

Try something like '((?:[^']|'')*?)'(?!') (demo on 101regex)

Upvotes: 0

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