CODEWITHSUNDEEP
c++inheritancepolymorphismbase-class
user542687
user542687

Reputation:

C++: Protected Class Constructor

If a class is always going to be inherited, does it make sense to make the constructor protected?

class Base
{
protected:
    Base();
};

class Child : protected Base
{
public:
    Child() : Base();
};

Thanks.

Upvotes: 9

Views: 7594

Answers (2)

Sarfaraz Nawaz
Sarfaraz Nawaz

Reputation: 361472

That only makes sense if you don't want clients to create instances of Base, rather you intend it to be base-class of some [derived] classes, and/or intend it to be used by friends of Base (see example below). Remember protected functions (and constructors) can only be invoked from derived classes and friend classes.

class Sample;
class Base
{
    friend class Sample;
protected:
    Base() {}
};

class Sample
{
 public:
   Sample()
   {
      //invoking protected constructor
      Base *p = new Base();
   }
};

Upvotes: 11

GManNickG
GManNickG

Reputation: 503913

If it's always going to be a base (a "mixin"), yes. Keep in mind a class with pure virtual functions will always be a base, but you won't need to do this since it cannot be instantiated anyway.

Also, give it either a public virtual destructor or a protected non-virtual destructor.

Upvotes: 4

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