Paxenos
Paxenos

Reputation: 2866

How can I get column names from a table in Oracle?

I need to query the database to get the column names, not to be confused with data in the table. For example, if I have a table named EVENT_LOG that contains eventID, eventType, eventDesc, and eventTime, then I would want to retrieve those field names from the query and nothing else.

I found how to do this in:

But I need to know: how can this be done in Oracle?

Upvotes: 225

Views: 939202

Answers (28)

semaphore
semaphore

Reputation: 99

If you use "Oracle SQL Developer" type the name of the table, place your cursor over that table name and press Shift+F4. It will open a popup window with all the column names for that table.

Upvotes: 0

Amrutesh Mishra
Amrutesh Mishra

Reputation: 11

In Oracle SQL Developer,

  1. You can get the column names by opening the table view, by expanding the Connections option in the Left Hand Pane. Then Navigate to the table and Click on it.

  2. This will open the Table View, listing out all the Column names and their details.

Connections

Upvotes: 0

DSH
DSH

Reputation: 1139

This will return all tables:

SELECT table_name, column_name, data_type, data_length
FROM ALL_TAB_COLUMNS
WHERE TABLE_NAME = 'YOUR_TABLE_NAME'

Upvotes: 0

Renaud Kern
Renaud Kern

Reputation: 1156

In Oracle, there is two views that describe columns:

  • DBA_TAB_COLUMNS describes the columns of all tables, views, and clusters in the database.

  • USER_TAB_COLUMNS describes the columns of the tables, views, and
    clusters owned by the current user. This view does not display the
    OWNER column.

Upvotes: 1

Sergey Golovchenko
Sergey Golovchenko

Reputation: 18681

You can do this:

describe EVENT_LOG

or

desc EVENT_LOG

Note: only applicable if you know the table name and specifically for Oracle.

Upvotes: 46

user3655399
user3655399

Reputation: 1

SELECT COLUMN_NAME 
FROM YourDatabase.INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_NAME = 'YourTableName'

Upvotes: -5

Etibar - a tea bar
Etibar - a tea bar

Reputation: 1962

you can run this query

SELECT t.name AS table_name,
SCHEMA_NAME(schema_id) AS schema_name,
c.name AS column_name
FROM sys.tables AS t
INNER JOIN sys.columns c ON t.OBJECT_ID = c.OBJECT_ID
WHERE c.name LIKE '%%' --if you want to find specific column write here 
ORDER BY schema_name, table_name;

Upvotes: 0

Dbo
Dbo

Reputation: 127

Mysql

SHOW COLUMNS FROM a_table_named_users WHERE Field REGEXP 'user_id|user_name|user_pass'

This will return a result something like this:

Field     |  Type        |   Null   |   Key   |   Default   |   Extra  
user_id      int(8)          NO         PRI       NULL          auto_increment
user_name    varchar(64)     NO         MUL       NULL
user_pass    varchar(64)     NO                   NULL

Then to pull out the values you can simply

fetch row[0]

This is also great for passing input dynamically since the REGEXP needs the '|' for multiple inputs, but is also a way to keeps data separated and easy to store/pass to classes/functions.

Try throwing in dummy data as well for security when sending it out and compare what was returned when receiving any errors.

Upvotes: 1

pals17
pals17

Reputation: 1

Try this

select * from sys.all_columns c join sys.objects o on c.object_id=o.object_id where o.name = 'TABLENAME' and c.name like '%COLUMN NAME%'

Upvotes: -1

carnust
carnust

Reputation: 621

Came across this question looking for access to column names on Teradata, so I'll add the answer for their 'flavour' of SQL:

SELECT ColumnName
FROM DBC.Columns
WHERE DatabaseName='DBASE_NAME'
AND TableName='TABLE_NAME';

The info is stored in the DBC dbase.

Getting data types is a little bit more involved: Get column type using teradata system tables

Upvotes: -2

expert one
expert one

Reputation: 37

SELECT COLUMN_NAME 'all_columns' 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_NAME='user';

Upvotes: 2

shieldstroy
shieldstroy

Reputation: 1327

For SQLite I believe you can use something like the following:

PRAGMA table_info(table-name);

Explanation from sqlite.org:

This pragma returns one row for each column in the named table. Columns in the result set include the column name, data type, whether or not the column can be NULL, and the default value for the column. The "pk" column in the result set is zero for columns that are not part of the primary key, and is the index of the column in the primary key for columns that are part of the primary key.

See also: Sqlite.org Pragma Table Info

Upvotes: 20

blue-sky
blue-sky

Reputation: 53896

Just select first row from the table , for oracle : select * from <table name> where rownum = 1;

Upvotes: -2

Jaisankar
Jaisankar

Reputation: 453

Even this is also one of the way we can use it

select * from product where 1 != 1

Upvotes: 4

bstricks
bstricks

Reputation: 923

For SQL Server:

SELECT [name] AS [Column Name]
FROM syscolumns
WHERE id = object_id('TABLE_NAME')

Upvotes: 2

Henry
Henry

Reputation: 29

SELECT A.COLUMN_NAME, A.* FROM all_tab_columns a 
WHERE table_name = 'Your Table Name'
AND A.COLUMN_NAME = 'COLUMN NAME' AND a.owner = 'Schema'

Upvotes: 2

Val
Val

Reputation: 11107

I did it like this

SELECT 
    TOP 0
    *
FROM
    Posts

It works even in http://data.stackexchange.com whose service tables I am not aware of!

Upvotes: -3

user2558588
user2558588

Reputation: 77

The answer is here: http://php.net/manual/en/function.mysql-list-fields.php I'd use the following code in your case:

$result = mysql_query("SHOW COLUMNS FROM sometable");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$fields = array();
if (mysql_num_rows($result) > 0) {
    while ($row = mysql_fetch_assoc($result)) {
        $fields[] = $row['Field'];
    }
}

Upvotes: 0

ssamuel68
ssamuel68

Reputation: 952

For MySQL, use

SELECT column_name 
FROM information_schema.columns 
WHERE 
table_schema = 'Schema' AND table_name = 'Table_Name'

Upvotes: 3

Rohit
Rohit

Reputation: 109

describe YOUR_TABLE;

In your case :

describe EVENT_LOG;

Upvotes: 5

jampez77
jampez77

Reputation: 5241

For Oracle

SELECT column_name FROM user_tab_cols WHERE table_name=UPPER('tableName');

Upvotes: 8

WEFX
WEFX

Reputation: 8572

You could also try this, but it might be more information than you need:

sp_columns TABLE_NAME

Upvotes: 1

user1464296
user1464296

Reputation:

select column_name,* from information_schema.columns
 where table_name = 'YourTableName'
order by ordinal_position

Upvotes: 3

Jom
Jom

Reputation: 1897

For SQL Server 2008, we can use information_schema.columns for getting column information

SELECT *
FROM   information_schema.columns
WHERE  table_name = 'Table_Name'
ORDER  BY ordinal_position  

Upvotes: 26

Eppz
Eppz

Reputation: 3226

In SQL Server...

SELECT [name] AS [Column Name]
FROM syscolumns
WHERE id = (SELECT id FROM sysobjects WHERE type = 'V' AND [Name] = 'Your table name')

Type = 'V' for views Type = 'U' for tables

Upvotes: 67

Sasha
Sasha

Reputation: 1190

The other answers sufficiently answer the question, but I thought I would share some additional information. Others describe the "DESCRIBE table" syntax in order to get the table information. If you want to get the information in the same format, but without using DESCRIBE, you could do:

SELECT column_name as COLUMN_NAME, nullable || '       ' as BE_NULL,
  SUBSTR(data_type || '(' || data_length || ')', 0, 10) as TYPE
 FROM all_tab_columns WHERE table_name = 'TABLENAME';

Probably doesn't matter much, but I wrote it up earlier and it seems to fit.

Upvotes: 9

baretta
baretta

Reputation: 7605

You can query the USER_TAB_COLUMNS table for table column metadata.

SELECT table_name, column_name, data_type, data_length
FROM USER_TAB_COLUMNS
WHERE table_name = 'MYTABLE'

Upvotes: 261

Jon Ericson
Jon Ericson

Reputation: 21525

That information is stored in the ALL_TAB_COLUMNS system table:

SQL> select column_name from all_tab_columns where table_name = 'DUAL';

DUMMY

Or you could DESCRIBE the table if you are using SQL*PLUS:

SQL> desc dual
Name                               Null?    Type
----------------------------------------------------- -------- ---------------------- -------------
DUMMY                               VARCHAR2(1)

Upvotes: 20

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