CODEWITHSUNDEEP
bashshelldocker
user1775718
user1775718

Reputation: 1578

How to diagnose "docker: invalid reference format" when calling "docker run"?

I'm trying to create a shell script to run a docker container and am struggling. My script is like this:

#!/bin/bash

if [ "$1" == "" ]; then
    echo "Usage > run.sh IMAGE NAME"
    echo
    echo "i.e. ./build.sh cd2:0.0.49"
    exit
fi

echo $1

docker run -it --rm \
-e NODE_PATH='./src'\
-e NODE_HOST='0.0.0.0'\
-e NODE_ENV='production'\
-e DOCKER=true\
-e PORT='8080'\
-e STAGING=true\
-e SENDGRID_API_KEY='<redacted>'\
-p 8080:8080 $1

When I run: bash run.sh cd2:0.0.50

I get: docker: invalid reference format: repository name must be lowercase.

Even if I do bash run.sh cd:0.0.50 it still fails (echo $1 results in cd2:0.0.50).

If I run docker run -it --rm -p 8080:8080 cd2:0.0.50 from the command line it works...

Can anyone help?

Upvotes: 7

Views: 28656

Answers (2)

Jthorpe
Jthorpe

Reputation: 10204

My issue had the same cause addressed by @Raman's answer, but a slightly different cause: Passing in an environment varialbe that had a space in it via

SOMETHING="hello world" # note the space character!
docker run --env SOMETHING=$SOMETHING -it my_image

And the resolution is just to quote the value (which works in Bash, anyway):

docker run --env something="$SOMETHING" -it my_image

Upvotes: 1

Raman Sailopal
Raman Sailopal

Reputation: 12917

The image name should be immediately after the -it options. Move the -it options to the end:

docker run \
-e NODE_PATH='./src' \
-e NODE_HOST='0.0.0.0' \
-e NODE_ENV='production' \
-e DOCKER=true \
-e PORT='8080' \
-e STAGING=true \
-e SENDGRID_API_KEY='<redacted>' \
-p 8080:8080 --rm -it $1

Upvotes: 11

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