CODEWITHSUNDEEP
java
hitain09
hitain09

Reputation: 19

Is it possible in java to get multiple inputs in a single line??

I am trying to get multiple inputs in a single code of line.. for example in c++, we could have it like -

int a,b,c;
cin>>a>>b>>c;

is it possible in java also??

Upvotes: 0

Views: 1669

Answers (1)

Adrian
Adrian

Reputation: 3134

You can use an array for this purpose, like: 

public static void main(String[] args) {
        int[] values = new int[3];
        Scanner in = new Scanner(System.in);
        for(int i = 0; i < values.length; i++) {
            values[i] = in.nextInt();
        }
        System.out.println(Arrays.toString(values));
    }

UPDATE 2

In java 8 the above solution can have a shorter version:

Scanner in = new Scanner(System.in);
Integer[] inputs = Stream.generate(in::nextInt).limit(3).toArray(Integer[]::new);

UPDATE 1

There is another way, which is closer to cin:

public class ChainScanner {
        private Scanner scanner;

        public ChainScanner(Scanner scanner) {
            this.scanner = scanner;
        }

        public ChainScanner readIntTo(Consumer<Integer> consumer) {
            consumer.accept(scanner.nextInt());
            return this;
        }

        public ChainScanner readStringTo(Consumer<String> consumer) {
            consumer.accept(scanner.next());
            return this;
        }
    }

    public class Wrapper {
        private int a;
        private int b;
        private String c;

        public void setA(int a) {
            this.a = a;
        } /* ... */
    }

    public static void main(String[] args) {
        ChainScanner cs = new ChainScanner(new Scanner(System.in));
        Wrapper wrapper = new Wrapper();

        cs.readIntTo(wrapper::setA).readIntTo(wrapper::setB).readStringTo(wrapper::setC);

        System.out.println(wrapper);
    }

Upvotes: 1

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