CODEWITHSUNDEEP
scalacollections
donkillme
donkillme

Reputation: 11

list.map can take a string in scala

Is str somehow implicitly converted to str.charAt, so the map function works?

val str = "abcdefghij"
println(List.range(0, 10).map(str));

Upvotes: 1

Views: 118

Answers (1)

prayagupadhyay
prayagupadhyay

Reputation: 31252

since str is Seq of character, .map on str will call given index.

eg.

scala> List.range(0, 10).map(str)
res0: List[Char] = List(a, b, c, d, e, f, g, h, i, j)

// or .apply
scala> List.range(0, 10).map(str.apply)
res7: List[Char] = List(a, b, c, d, e, f, g, h, i, j)

And str(index) gives the value for index, see StringOps#apply(index: Int): Char

scala> "my string"(4)
res5: Char = t

Other Array and Seq example, 

scala> val array = Array(1, 2, 3, 4, 5)
array: Array[Int] = Array(1, 2, 3, 4, 5)

scala> List.range(0, 4).map(array)
res1: List[Int] = List(1, 2, 3, 4)

scala> val list = Seq(10, 20, 30, 40, 50)
list: Seq[Int] = List(10, 20, 30, 40, 50)

scala> List.range(0, 4).map(list)
res3: List[Int] = List(10, 20, 30, 40)

Upvotes: 5

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