CODEWITHSUNDEEP
python
user1334609
user1334609

Reputation: 431

print object name, when object call a function inside the class

#!/usr/bin/env python  
class AA(object):
    def __init__(self):
        pass
    def y(self):
        pass

x=AA()
x.y()

When I execute x.y(), I want to print "This is 'x' call me", how should I do it ?

Upvotes: 0

Views: 1187

Answers (4)

TheoRet
TheoRet

Reputation: 31

I have posted a complete solution here:

https://stackoverflow.com/a/49331683/7386061

It works without parameters. For example you could just do:

class AA(RememberInstanceCreationInfo):
    def y(self):
        print("my name is '"+self.creation_name+"'")

x=AA()
x.y()
out: my name is 'x'

Upvotes: 0

Hara
Hara

Reputation: 1502

From @user1334609 's comment:

for example, we have lots of vm instance,vm1=AA(), vm1.run_cmd("xxxx"), vm2=AA(), vm2.run_cmd("") I want to know which vm are run some cmd

To know which VM has run the command you can just use the id(self), instead of trying to find the declared variable in code.

Two options you have now to see from which vm, command is running.

Option1: Add a member variable to class. This can give readability.

Option2: Use the id of self in y(). This avoids adding additional variable.

Example code:

#!/usr/bin/env python
class AA(object):
    def __init__(self, vmname):
        self.whoami = vmname

    def y(self):
        print "My Name is %s " % self.whoami # Option1
        print "My Id is %s " % id(self) # Option2


def main():
    vm1=AA("Yoda")
    vm1.y()
    vm2=AA("Boda")
    vm2.y()
    vm3=AA("Anakin")
    vm3.y()


if __name__ == '__main__':
    main()

This gives following output:

My Name is Yoda 
My Id is 139725977256656 
My Name is Boda 
My Id is 139725977256720 
My Name is Anakin 
My Id is 139725977256784

Upvotes: 0

Kallz
Kallz

Reputation: 3523

Everything is an object in Python, When you create an instance of the class it allocate memory location and that memory location is referenced by your x variable.The only object has memory location, variable doesn't have any memory location. Variable just refer to objects memory location

in your example, X is nothing just reference to your memory location

if define a variable

a = 2

that means a reference to 2

a = 1

that means a now reference to 1

Assigning one variable to another makes a new tag bound to the same value as shown below.

b = a

that means a and b both reference to 1

id() in python return memory location 

print id(a)
print id(b)

output

140621897573617
140621897573617

Example 1:

>>> s1 = 'hello'

>>> s2 = 'hello'

>>> id(s1), id(s2) 
(4454725888, 4454725888)

>>> s1 == s2 True

>>> s1 is s2 True

>>> s3 = 'hello, world!'

>>> s4 = 'hello, world!'

>>> id(s3), id(s4) (4454721608, 4454721664)

>>> s3 == s4 True

>>> s3 is s4 False

Example 2

>>> class Foo:
...     pass
...
>>> bar = Foo()
>>> baz = Foo()
>>> id(bar)
140730612513248
>>> id(baz)
140730612513320

result

Name of object or instance is nothing just reference to memory location

Upvotes: 0

ricristian
ricristian

Reputation: 536

I hope that this will solve your issue

#!/usr/bin/env python


class AA(object):
    def __init__(self):
        pass

    def y(self, name):
        self.name = name
        print("This is %s call me" % name)


x = AA()
x.y("Tarzan")

Upvotes: 1

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