CODEWITHSUNDEEP
tensorflow
user8381550
user8381550

Reputation: 229

How to get weights in tf.layers.dense?

I wanna draw the weights of tf.layers.dense in tensorboard histogram, but it not show in the parameter, how could I do that?

Upvotes: 21

Views: 28468

Answers (8)

Ahmed Ousama
Ahmed Ousama

Reputation: 1

Try to make a loop for getting the weight of each layer in your sequential network by printing the name of the layer first which you can get from: model.summary()
Then u can get the weight of each layer running this code:

for layer in model.layers:
    print(layer.name)
    print(layer.get_weights())

Upvotes: 0

Adi Shumely
Adi Shumely

Reputation: 397

in TF2 weights will output a list in length 2

weights_out[0] = kernel weight

weights_out[1] = bias weight

the second layer weight (layer[0] is the input layer with no weights) in a model in size: 50 with input size: 784

inputs = keras.Input(shape=(784,), name="digits")
x = layers.Dense(50, activation="relu", name="dense_1")(inputs)
x = layers.Dense(50, activation="relu", name="dense_2")(x)
outputs = layers.Dense(10, activation="softmax", name="predictions")(x)

model = keras.Model(inputs=inputs, outputs=outputs)
model.compile(...)
model.fit(...)

kernel_weight = model.layers[1].weights[0]
bias_weight = model.layers[1].weights[1]
all_weight = model.layers[1].weights
print(len(all_weight))                      #  2
print(kernel_weight.shape)                  # (784,50)
print(bias_weight.shape)                    # (50,)

Upvotes: 0

Kristof
Kristof

Reputation: 406

In TF 2 if you're inside a @tf.function (graph mode):

weights = optimizer.weights

If you're in eager mode (default in TF2 except in @tf.function decorated functions):

weights = optimizer.get_weights()

Upvotes: 0

P-Gn
P-Gn

Reputation: 24581

The weights are added as a variable named kernel, so you could use

x = tf.dense(...)
weights = tf.get_default_graph().get_tensor_by_name(
  os.path.split(x.name)[0] + '/kernel:0')

You can obviously replace tf.get_default_graph() by any other graph you are working in.  

Upvotes: 33

Matt Cremeens
Matt Cremeens

Reputation: 5151

Is there anything wrong with

model.get_weights()

After I create a model, compile it and run fit, this function returns a numpy array of the weights for me.

Upvotes: 1

Animesh Karnewar
Animesh Karnewar

Reputation: 436

The latest tensorflow layers api creates all the variables using the tf.get_variable call. This ensures that if you wish to use the variable again, you can just use the tf.get_variable function and provide the name of the variable that you wish to obtain.

In the case of a tf.layers.dense, the variable is created as: layer_name/kernel. So, you can obtain the variable by saying:

with tf.variable_scope("layer_name", reuse=True):
    weights = tf.get_variable("kernel") # do not specify
    # the shape here or it will confuse tensorflow into creating a new one.

[Edit]: The new version of Tensorflow now has both Functional and Object-Oriented interfaces to the layers api. If you need the layers only for computational purposes, then using the functional api is a good choice. The function names start with small letters for instance -> tf.layers.dense(...). The Layer Objects can be created using capital first letters e.g. -> tf.layers.Dense(...). Once you have a handle to this layer object, you can use all of its functionality. For obtaining the weights, just use obj.trainable_weights this returns a list of all the trainable variables found in that layer's scope.

Upvotes: 10

mic
mic

Reputation: 953

I am going crazy with tensorflow.

I run this:

sess.run(x.kernel)

after training, and I get the weights.

Comes from the properties described here.

I am saying that I am going crazy because it seems that there are a million slightly different ways to do something in tf, and that fragments the tutorials around.

Upvotes: 5

Yerrick
Yerrick

Reputation: 151

I came across this problem and just solved it. tf.layers.dense 's name is not necessary to be the same with the kernel's name's prefix. My tensor is "dense_2/xxx" but it's kernel is "dense_1/kernel:0". To ensure that tf.get_variable works, you'd better set the name=xxx in the tf.layers.dense function to make two names owning same prefix. It works as the demo below:

l=tf.layers.dense(input_tf_xxx,300,name='ip1')
with tf.variable_scope('ip1', reuse=True):
    w = tf.get_variable('kernel')

By the way, my tf version is 1.3.

Upvotes: 9

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