CODEWITHSUNDEEP
swiftstring
Sam
Sam

Reputation: 2446

Case-sensitive character replacement in a Swift string

I need to replace characters in a Swift string case-sensitively.

I've been using the replacingOccurrences(of:with:options:range:) built-in string function to change every "a" to a "/a/", every "b" to a "/b/", and so on, like this:

stringConverted = stringConverted.replacingOccurrences(of: "a", with: "/a/", options: [])

Then I change every "/a/" to its corresponding letter, which is "a". I change every "/b/" to its corresponding letter, which is "q", and so on.

My problem is that I need this replacement to be case-sensitive. I've looked this up, but I've tried what I found and it didn't help.

Do I need to use the range argument? Or am I doing something else wrong?

Upvotes: 2

Views: 3114

Answers (2)

Mike Zriel
Mike Zriel

Reputation: 1865

Try this:

let oldString = "Change This, change this"

let newString = myString.replacingOccurrences(of: "change this", with: "to this", options: .caseInsensitive)

Both work with options: .caseInsensitive

Upvotes: 0

Hussain Shabbir
Hussain Shabbir

Reputation: 15015

As @Orkhan mentioned you can pass options: .caseInsensitive like below

let a = "a"
let start = a.index(a.startIndex, offsetBy: 0)
let end = a.index(a.startIndex, offsetBy: a.count)
let range = start..<end
let value = a.replacingOccurrences(of: "a", with: "/a", options: .caseInsensitive, range: range)
print(value)

Upvotes: 10

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