CODEWITHSUNDEEP
jquery
Anna Jeanine
Anna Jeanine

Reputation: 4125

jQuery.inArray always returns -1

I am trying to make a DataTables multiple row selection going, in which they use the code: 

if ( $.inArray(1, 1) !== -1 ) {
   $(row).addClass('selected');
}

To check if certain row have already been selected. However, every equation which I put in the $.inArray return -1. I have tried some in the console of my browser such as $.inArray(1,3), $.inArray([1],[3]), $.inArray(["1"],["3"]), $.inArray(1,1), $.inArray([1],[1]) but all return -1! According to the documentation of jQuery this should be possible...

Source

Upvotes: 0

Views: 65

Answers (1)

hallleron
hallleron

Reputation: 1992

You are simply using it wrong =)

The first argument is the value you want to find and the second argument is the actual Array to search the value in.

So you should have something like:

var array = [1, 2, 3];

... $.inArray(1, array) ...

Upvotes: 1

Related Questions