CODEWITHSUNDEEP
javamavenjar
maxday
maxday

Reputation: 1332

Run a jar from another jar

I have a jar which contains another jar, my goal is to run this "inside jar" from the global jar.

I have this method which retrieves the full path of the jar contained in the jar 

private static String getRealPathFromResourceName(String fileName) throws IOException {
    ClassLoader cl = Main.class.getClassLoader();
    URL resource = cl.getResource(fileName);
    String path = resource.getPath();
    return path;
}

Then I run this : 

public static boolean exportFullPeriod(CheckConfiguration checkConfig) throws IOException {
    final String cmdLine = buildExportCommandLine(checkConfig);
    try {
        Process process = Runtime.getRuntime().exec(cmdLine);
        ....
    } catch (
        ...
}

where build exportCommandLine builds the full command line using the previous method, the full output is : 

java -jar file:/C:/Users/xxx/target/module-backup-1.0.jar!/export-1.1.jar -dbUrl jdbc:mysql://localhost:3306/test -dbPassword test -dbUser test

The error I get is the following 

Error: Unable to access jarfile file:/C:/Users/xxx/target/module-backup-1.0.jar!/export-1.1.jar

How can I reference the jar inside my jar to call it ?

Upvotes: 1

Views: 801

Answers (1)

tgkprog
tgkprog

Reputation: 4598

The java process does not know how to extract a jar from a jar and run a class in the inner jar. You will need to extract it to a directory where the outer jar is running (a dynamic variable). Then create the command line based on that and finally run it.

So if you have /u/myapps/app.jar that has a entry "someDir/anotherApp.jar" First extract that to a directory, say "/u/myapps/tmp/someDir/anotherApp.jar", then run it from here.

See java.util.zip package for how to open a jar (or zip) file from java.

if you do not have write permission to "/u/myapps/tmp/" then try using the tmp entry from System.getProperties()

Upvotes: 2

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