Reputation: 529
My question:
This answer explains how to convert a String containing elements separated by spaces into an array.
let numbers = "1 2 3 4"
let numbersArray = numbers.components(separatedBy: " ")
print(numbersArray)
// output: ["1", "2", "3", "4"]
// but I want: [1, 2, 3, 4]
However, I'm trying to make an array without quotation marks, because I'm making an array of numbers, not strings.
My attempts:
I tried removing all quotation marks from numbersArray
, but this didn't work as it's an array, not a string.
numbersArray.replacingOccurrences(of: "\"", with: "") // won't work
I tried something different: I tried adding each element in the array to a new array, hoping that new array wouldn't contain quotation marks. I got an error, though:
let numbers = "1 2 3 4" // string to be converted into array without quotes
let numbersArray = numbers.components(separatedBy: " ") // convert string into array with quotes
var newNumbersArray = [String]() // new blank array (which will be without quotes)
for i in numbersArray { // for each item in the array with quotes
newNumbersArray += i // (hopefully) add the item in the new array without quotes
}
print(newNumbersArray) // print the new array
This gives me an error:
Swift:: Error: cannot convert value of type '[String]' to expected argument type 'inout String'
newNumbersArray += i
Upvotes: 1
Views: 1422
Reputation: 6223
Swift 3.0
Try this.. Chaining method makes it easy.
let temp = "1 2 3 4 5 6"
var numbers: [Int] = []
temp.components(separatedBy: " ").forEach { numbers.append(Int($0)!) }
print(numbers) //[1, 2, 3, 4, 5, 6]
Upvotes: 1
Reputation: 73236
You can apply a flatMap
call on the [String]
array resulting from the call to components(separatedBy:)
, applying the failable init(_:radix:)
of Int
in the body of the transform closure of the flatMap
invokation:
let strNumbers = "1 2 3 4"
let numbersArray = strNumbers
.components(separatedBy: " ")
.flatMap { Int($0) }
print(numbersArray) // [1, 2, 3, 4]
print(type(of: numbersArray)) // Array<Int>
Upvotes: 2
Reputation: 1368
You can try this:
var newArray = [Int]()
for item in numbersArray{
newArray.append(Int(item))
}
print(newArray)
Upvotes: 1