CODEWITHSUNDEEP
bashcurl
abdul rahman safari
abdul rahman safari

Reputation: 21

bash - assign variable to curl get request

#!/bin/bash
while IFS='' read -r line || [[ -n "$line" ]]; do
    echo "Text read from file: $line"
    curl 'https://shoesworkshop.net/libraries/ajax/ajax.invoice.php?act=viewallinvoice&invoiceid="${line}"&sEcho=1&iColumns=8&iDisplayStart=0&iDisplayLength=20&bRegex=false&bRegex_0=false&bSearchable_0=true&bRegex_1=false&bSearchable_1=true&bRegex_2=false&bSearchable_2=true&bRegex_3=false&bSearchable_3=true&bRegex_4=false&bSearchable_4=true&bRegex_5=false&bSearchable_5=true&bRegex_6=false&bSearchable_6=true&bRegex_7=false&bSearchable_7=true&iSortCol_0=0&sSortDir_0=asc&iSortingCols=1&bSortable_0=true&bSortable_1=true&bSortable_2=true&bSortable_3=true&bSortable_4=true&bSortable_5=true&bSortable_6=true&bSortable_7=true' -H 'Host: shoesworkshop.net'| sed  's/^[^[[]*:/:/'
done < "$1"

inside $line there is a value like this

AAAAA
SSSSS
DDDDD

and i want to pass $line into curl command can someone help me how? i tried "'${line}'" and '${line}' and it still not working i want to make a repeat call using curl get request from the url using variable from $line

Upvotes: 2

Views: 1157

Answers (1)

randomir
randomir

Reputation: 18687

For simple URLs, one way is to just use double quotes for the complete URL, including your variable expansion, ${line}, like this:

curl "https://shoe...&invoiceid=${line}&sEcho=1&iCo...table_7=true"

(Under single quotes, your shell variable line is not expanded.)

If your URL contains shell-special characters like $, it's best to combine both single and double quotes (and concatenate several strings, like explained here). For Example:

curl 'https://shoe...&invoiceid='"$line"'&sEcho=1&iCo...table_7=true'
#     ^------ fixed part ------^  ^var^  ^------- fixed part ------^

However, if your variable contains characters that have to be URL-encoded (like space, &, ?, etc.) it's best to let curl handle that with --data-urlencode option. When called with this option, curl will default to POST method, but you can override this with -G, in which case your parameters will be appended to URL query. For example:

line="1&2?3 4"
curl "http://httpbin.org/get?x=1&y=2" --data-urlencode z="$line" -G

produces the right URL:

http://httpbin.org/get?x=1&y=2&z=1%262%3F3%204

Your script, fixed:

#!/bin/bash
while IFS='' read -r line || [[ -n "$line" ]]; do
    echo "Text read from file: $line"
    curl --data-urlencode invoiceid="$line" -G 'https://shoesworkshop.net/libraries/ajax/ajax.invoice.php?act=viewallinvoice&sEcho=1&iColumns=8&iDisplayStart=0&iDisplayLength=20&bRegex=false&bRegex_0=false&bSearchable_0=true&bRegex_1=false&bSearchable_1=true&bRegex_2=false&bSearchable_2=true&bRegex_3=false&bSearchable_3=true&bRegex_4=false&bSearchable_4=true&bRegex_5=false&bSearchable_5=true&bRegex_6=false&bSearchable_6=true&bRegex_7=false&bSearchable_7=true&iSortCol_0=0&sSortDir_0=asc&iSortingCols=1&bSortable_0=true&bSortable_1=true&bSortable_2=true&bSortable_3=true&bSortable_4=true&bSortable_5=true&bSortable_6=true&bSortable_7=true' -H 'Host: shoesworkshop.net' | sed 's/^[^[[]*:/:/'
done < "$1"

Upvotes: 2

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