Reputation: 1459
How do you create a layout field using sitecore fakedb? I have the code below but it does not work.
The below code throws an error "the item is not a layout/rendering field"
var template = new Sitecore.FakeDb.DbTemplate("themes", Templates.SiteTheme.ID);
var home = new Sitecore.FakeDb.DbItem("home", new Sitecore.Data.ID());
var lookUpField = new Sitecore.FakeDb.DbField("link", Templates.SiteTheme.Fields.SiteTheme) {
Type = "Rendering"
};
lookUpField.Value = home.ID.ToString();
var site = new Sitecore.FakeDb.DbItem("site", new Sitecore.Data.ID(), Theming.Templates.SiteTheme.ID) {
lookUpField
};
home.Add(site);
db.Add(home);
var themesItem = db.GetItem("/sitecore/content/home/site");
var layout = new LayoutField(themesItem.Fields["link"]);
var value = layout.Value;
Xunit.Assert.NotNull(value);
Upvotes: 2
Views: 223
Reputation: 1241
Something like that:
[TestCase]
public void FooLayout()
{
// arrange
var itemId = ID.NewID;
using (var db = new Db
{
new DbItem("Some Item", itemId)
{
new DbField(Sitecore.FieldIDs.LayoutField) { Value = "{presentation-xml}" }
}
})
{
var item = db.GetItem(itemId);
// act
// assert
item[Sitecore.FieldIDs.LayoutField].Should().Be("{presentation-xml}");
}
}
Note: Should().Be() methods come from https://www.nuget.org/packages/FluentAssertions/
Upvotes: 2