CODEWITHSUNDEEP
jqueryregexextract
George
George

Reputation: 121

get value from second pair of brackets, ignore data from first pair

I'm looking for a way to get the value from a second pair of brackets.

this is an example : var foo = "bar - (cocktails) - (drunk);

Now I need the value "drunk", but not the value "cocktails".

I managed to get the value from the first pair, but still struggling to get the data from the second pair.

This is my code to extract the first value :

 var foo = "bar - (cocktails) - (drunk)";
 chosenfoo = foo;
 filterOut  = /\((.*)\)/i;
 var strippedFoo=  chosenfoo.match(filterOut)[1];
 $('#foobarfield').val(strippedFoo);

I was too brave to think that changing the number 1 to 2 would solve it. :)

When the value would be "bar - (cocktails)" then I'll get it right, like "cocktails", but with the previously given var with both pairs of brackets the result value for this code is :

cocktails) - (drunk

not exactly what I want :(

anyone can help me on this one?

Upvotes: 0

Views: 77

Answers (4)

Kunal Patel
Kunal Patel

Reputation: 119

Look at below example

var foo = "bar - (cocktails) - (drunk)";
var strippedFoo=  foo.match(/\((.*?)\)/gi)[1].replace(/\(|\)/g, "");;
alert(strippedFoo)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Upvotes: 1

Egan Wolf
Egan Wolf

Reputation: 3573

You can get the last bracket with this:

\((?!.*\().*\)

And with this one you can get the last complete bracket even if there is a non-complete bracket (just one ( or )) at the end:

\((?!.*\(.*\)).*?\)

DEMO

Update to match the content of brackets:

\((?!.*\(.*\))(.*?)\)

Upvotes: 0

fdomn-m
fdomn-m

Reputation: 28611

You can get what you want with two changes:

  • add /g for global matches (multiple matches) otherwise it stops on first match
  • add ? to mean (basically) 'shortest match possible'

As in:

/\((.*?)\)/gi

With the change to /g, the return is an array of matches, so first is [0] and second [1]

Snippet:

var foo = "bar - (cocktails) - (drunk)";
chosenfoo = foo;
filterOut  = /\((.*?)\)/gi;
var strippedFoo=  chosenfoo.match(filterOut)[1];
$('#foobarfield').text(strippedFoo);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id='foobarfield'></div>

Upvotes: 1

Lorenzo Catalano
Lorenzo Catalano

Reputation: 477

you are matching everything between the 1st and the very last parenthesis. fix your regex like this

/\((.*?)\)/gi

and you should end up with 2 captures

Upvotes: 0

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