Reputation: 2175
I have two forms(in one page). On first form there are two buttons NEXT and BACK. On clicking on the next i will render next form on page. I am using ng-if for this condition.
<form name="otpform" novalidate ng-if="renderotpform">
<fieldset ng-disabled="otpdisable">
<div class="middle-container steps fourth-step overflow-hidden" id="divotp">
<input class="" type="text" name="otp" placeholder="{{ 'OTP' | translate }}" ng-model="otp" required >
<input type="button" value="{{ 'BACK' | translate }}" class="brown-button" ng-click="gotoAck()">
<input type="submit" value="{{ 'NEXT' | translate }}" class="blue-button" ng-click="checkotp()">
</div>
</fieldset>
</form>
Below is my js code.
$scope.checkotp = function () {
debugger;
var otpvalue;
$scope.otp = {};
otpvalue = $scope.otp; //undefined
}
When I try to access the otp model I am getting undefined property. On previous form I have next button. Inside next button I have $scope.renderotpform = true;
so that above form is shown. May I know why I am not able to access OTP in the above code?
Upvotes: 3
Views: 1631
Reputation: 6630
ng-if
creates its own scope. So the otp inside ng-if
is not binded directly to the controller.You can either bind the model to an object or use controller as syntax. The controller as syntax implicitly takes care of the dot rule.
For more info:
var app = angular.module("myApp", []);
app.controller("myCtrl", function($scope) {
var vm=this;
vm.renderotpform = true;
vm.checkotp = function() {
console.log(vm.otp);
}
});
<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl as vm">
<form name="otpform" novalidate ng-if="vm.renderotpform">
<fieldset ng-disabled="otpdisable">
<div class="middle-container steps fourth-step overflow-hidden" id="divotp">
<input class="" type="text" name="otp" ng-model="vm.otp" required>
<input type="button" value="BACK" class="brown-button" ng-click="vm.gotoAck()">
<input type="submit" value="NEXT" class="blue-button" ng-click="vm.checkotp()">
</div>
</fieldset>
</form>
</div>
Upvotes: 2
Reputation: 3232
Make all ng-models of the Form from one Object..
It would work and there are other advantages for this like you could easily reset and post data with just one object.:-
var app = angular.module("myApp", []);
app.controller("myCtrl", function($scope) {
$scope.formData = {};
$scope.renderotpform = true;
$scope.checkotp = function() {
console.log($scope.formData.otp);
}
});
<!DOCTYPE html>
<html>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.6.4/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl">
<form name="otpform" novalidate ng-if="renderotpform">
<fieldset ng-disabled="otpdisable">
<div class="middle-container steps fourth-step overflow-hidden" id="divotp">
<input class="" type="text" name="otp" ng-model="formData.otp" required>
<input type="button" value="BACK" class="brown-button" ng-click="gotoAck()">
<input type="submit" value="NEXT" class="blue-button" ng-click="checkotp()">
</div>
</fieldset>
</form>
</div>
Upvotes: 1