CODEWITHSUNDEEP
pythondjango
Leolo
Leolo

Reputation: 577

Django: reverse() does not find view with args/kwargs given

There are a few posts related to my problem. However, none seems to solve the following issue:

I have defined urls in myapp/urls.py:

app_name = "myapp"
urlpatterns=[
    url(r'^$', views.index, name="index"),
    url(r'^adduser/$', views.addUser, name="adduser"),
    ]

and corresponding views in myapp/views.py:

def index(request, status_msg=None, error_msg=None):
    return HttpResponse(render(request, "myapp/index.html", 
                               context={"error_message":error_msg, "status_message":status_msg})) 

def addUser(request):
    try:
        uname=request.POST["user_name"]
    except KeyError:
        url = reverse("myapp:index", args=(None, "No user name specified."))
        return HttpResponseRedirect(url)
    # ... adding user to db ...
    url = reverse("myapp:index", args=("Added user '%s'"%uname,))
    return HttpResponseRedirect(url)

Either variant of passing arguments to index() from the redirect in addUser() yields an error of the kind

Reverse for 'index' with arguments '(None, u'No user name specified.')' not found. 1 pattern(s) tried: [u'myapp/$']

I don't get what I'm doing wrong here. Seems the index view is found but not recognized to allow any arguments aside the request?

Using kwargs instead of args does not help, either.

Any suggestions are highly appreciated. Thanks already!

Upvotes: 0

Views: 1913

Answers (1)

Eugene Yarmash
Eugene Yarmash

Reputation: 149776

Your URL doesn't seem to support arguments (i.e captured groups in the regex). Therefore you should be using just:

reverse("myapp:index")

Check the docs for the reverse() function here.

Upvotes: 1

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