CODEWITHSUNDEEP
javascriptjquerydetach
Federico
Federico

Reputation: 1422

Removing DOM and add it back again

I have a simple JS function that removes certain classes while clicking on a "filter menu". The problem is that I don't know how to show those removed classes once I click on "All" i.e.

I can't use display:none, opacity:0 or visibility:hidden, I need to completely remove the DOM.

Thanks for any help.

$(document).on("click",".all",function(){$(".campaign,.editorial,.lookbook,.portrait").appendTo("body")})
$(document).on("click",".cam",function(){$(".editorial,.lookbook,.portrait").detach()})
$(document).on("click",".edi",function(){$(".campaign,.lookbook,.portrait").detach()})
$(document).on("click",".loo",function(){$(".campaign,.editorial,.portrait").detach()})
$(document).on("click",".por",function(){$(".campaign,.editorial,.lookbook").detach()})
.all,.cam,.edi,.loo,.por {cursor:pointer}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class=all>All</div>
<div class=cam>Campaign</div>
<div class=edi>Editorial</div>
<div class=loo>Lookbook</div>
<div class=por>Portrait</div><br>

<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>

Upvotes: 3

Views: 8978

Answers (2)

berkay kılı&#231;
berkay kılı&#231;

Reputation: 160

https://jsfiddle.net/wingsofwind/g579m7ux/

You can collect removed elements into array than remove them by using remove()

You can append them back into the body later on. 

/* remove all*/

var allelements = [];  
$("div").each(function(){
  allelements.push($(this));  // we push all divs into an array than remove them
  $(this).remove();
});


/* add back */
setTimeout(function(){ // You can remove This

for(var i = 0 ; i<allelements.length; i++){
    $("body").append(allelements[i]); // we append all elements back into body 
}

},1000) // also remove This
.all,.cam,.edi,.loo,.por {cursor:pointer}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class=all>All</div>
<div class=cam>Campaign</div>
<div class=edi>Editorial</div>
<div class=loo>Lookbook</div>
<div class=por>Portrait</div><br>

<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>
<div class=campaign>CAMPAIGN</div>
<div class=editorial>EDITORIAL</div>
<div class=lookbook>LOOKBOOK</div>
<div class=portrait>PORTRAIT</div>

Upvotes: 3

Rohit Sharma
Rohit Sharma

Reputation: 3334

It may be possible by using temporary variable.

$(document).ready(function() {
	var toBeDeleted = $('.p-tag');
	$('#buttonRemove').on('click',function(event) {
		event.preventDefault();
		$(toBeDeleted).remove();
	});
	$('#buttonAdd').on('click',function(event) {
		event.preventDefault();
		if ($('body').find('.p-tag').length == 0) {
			$('body').append(toBeDeleted);
		}
	});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<button type="button" class="" id="buttonRemove">Remove</button>
<button type="button" class="" id="buttonAdd">Add</button>
<p class="p-tag">Lorem ipsum dolor sit amet, consectetur adipisicing elit, sed do eiusmod
tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam,
quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo
consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse
cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non
proident, sunt in culpa qui officia deserunt mollit anim id est laborum.</p>

Upvotes: 0

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