Reputation: 33
I am trying to put a drop down menu but for some reason it is not able to get the selected option . I send it to a PHP server using POST method.
<center><form style="align:left;"action="signuphand.php" method="post" accept-charset="utf-8">
<label>Enter name of teacher: </label><input type="text" name="name" value="" placeholder="Name">
<br />
<label>Enter branch:
<select name="branch">
<option value="SELECT BRANCH">SELECT BRANCH</option>
<option value="ECE">ECE</option>
<option value="CSE">CSE</option>
<option value="MECH">MECH</option>
<option value="E & I">E & I</option>
<option value="CIVIL">CIVIL</option>
<option value="ELECTRICAL">ELECTRICAL</option>
</select>
</label>
<br />
<label>Enter role:
<select id="role">
<option value="SELECT ROLE">SELECT ROLE</option>
<option value="teacher">teacher</option>
<option value="student">student</option>
</select>
and PHP is
if (isset($_POST['register']))
{
$name= $_POST['name'];
if (isset($_POST['branch'])){
$branch= $_POST['branch'];
}
$user = $_POST['username'];
$pass = $_POST['password'];
$pass2= $_POST['password1'];
if (isset($_POST['branch'])){
$role= $_POST['role'];
}
But the problem is still not resolved. The branch and role columns are still empty in my table. Folowed this technique How to get a value of HTML drop down menu using PHP?
and many others still problem persists please help. Used isset beacause without it I was getting undefined index for 'role' and 'branch'.
Upvotes: 1
Views: 34
Reputation: 646
For the second select tag, you used the "id" attribute instead of "name". So you should change that to name firstly:
<select name="role">
<option value="SELECT ROLE">SELECT ROLE</option>
<option value="teacher">teacher</option>
<option value="student">student</option>
</select>
Secondly, in your php file, you checked if "branch" was set instead of "role". So fix that too:
if (isset($_POST['register']))
{
$name= $_POST['name'];
if (isset($_POST['branch'])){
$branch= $_POST['branch'];
}
$user = $_POST['username'];
$pass = $_POST['password'];
$pass2= $_POST['password1'];
if (isset($_POST['role'])){
$role= $_POST['role'];
}
If it still doesn't work, consider posting your whole code, maybe something is wrong there.
Upvotes: 1