CODEWITHSUNDEEP
phpvariablesforeachisset
stangerup
stangerup

Reputation: 19

php check isset from array

I'm trying to check if a variable is existing, and if not - then define it.

$checkarray = array($demo1, $demo2, $demo3);

foreach ($checkarray as $checkkey) {
  if (!isset($checkkey)) {
    $checkkey = 'none';
  }
}

But I'm just getting this error: *Notice: Undefined variable: demo1 (and so on...)

This is bascially what i'm trying to achive...

if (!isset($demo1)) {
  $demo1 = 'none';
 }

if (!isset($demo2)) {
  $demo2 = 'none';
 }

if (!isset($demo3)) {
 $demo3 = 'none';
}

But it's not pretty.

Any ideas?

Cheers Kris

Upvotes: 1

Views: 1852

Answers (1)

ᴄʀᴏᴢᴇᴛ
ᴄʀᴏᴢᴇᴛ

Reputation: 2999

You have to use the var name in your check array and not the var itself. This is called Variable variable

Then you can do something like this : 

$checkarray = array('demo1', 'demo2', 'demo3');

foreach ($checkarray as $checkkey) {
  if (!isset($$checkkey)) {
    $$checkkey = 'none';
  }
}

Upvotes: 1

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