CODEWITHSUNDEEP
phpcookies
Magiranu
Magiranu

Reputation: 309

How to check if $_COOKIE is filled or empty?

I just want to check if $_COOKIE has my actual cookie or not.

On Stackoveflow I read a lot about not to use empty() because it returns true when 0 is given which could be the case for a cookie. And many more, see: LainIwakura's answer.

If my client tries to access a page and he has not a cookie, he should get blocked.

public function index($request, $response)
{           
    if($_COOKIE != " ") {       
        // Okay
    } else {        
        return "Please log in first";
    }        
}

If I var_dump[$_COOKIE] I get this:

array(0) 
{ 
}

And when I log in first, I get this:

array(1) {
  ["AuthSession"]=>
  string(44) "Ym9iOjU5ODhFN0E2Ov0k6qKicxKpkePKi1AjlXglURFm"
}

My if($_COOKIE != " ") doesn't work and empty() is also not a solution for this case. if(isset($_COOKIE)) is also not working, because there seems to be always an instance of this variable whether it is filled or not. Which kind of solution is left to check if the cookie is there or not from your opinion?

Upvotes: 0

Views: 844

Answers (2)

user8371079
user8371079

Reputation:

The best way would be to check whether or not the actual cookie you're creating ('AuthSession') has been set, rather than checking if $_COOKIE is set or has a count > 0. If you haven't explicitly created that cookie, it will not be set, which is not the case with $_COOKIE.

public function index($request, $response)
{           
    if(isset($_COOKIE['AuthSession']) {       
        // Okay
    } else {        
        return "Please log in first";
    }        
}

Upvotes: 2

Ben Shoval
Ben Shoval

Reputation: 1750

Use: 

isset( $_COOKIE )

to see if it there is a cookie

Use

( count( $_COOKIE ) === 0 ) === FALSE

to check that it isn't empty

Therefore, your code should look like:

public function index($request, $response)
{           
    if( isset( $_COOKIE ) and ( ( count( $_COOKIE ) === 0 ) === FALSE ) ) {       
        // Okay
    } else {        
        return "Please log in first";
    }        
}

Upvotes: 0

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