Reputation: 369
I want to have a Context Menu when clicking an Item in my ListView
<ListView x:Name="resultsView" Grid.Column="1" Margin="10" Grid.Row="1" FontFamily="Verdana" FontSize="14">
<ListView.ContextMenu>
<ContextMenu FontFamily="Verdana" FontSize="14">
<MenuItem Header="Open Folder" Click="openFolder_Click" FontFamily="Verdana" FontSize="14"/>
<Separator/>
<MenuItem Header="Copy Path" Click="copyPath_Click" FontFamily="Verdana" FontSize="14"/>
</ContextMenu>
</ListView.ContextMenu>
<ListView.View>
<GridView x:Name="gridView">
<GridViewColumn x:Name="name" Header="Name" DisplayMemberBinding="{Binding Name}"/>
<GridViewColumn x:Name="folder" Header="Folder" DisplayMemberBinding="{Binding Folder}"/>
<GridViewColumn x:Name="location" Header="Path" DisplayMemberBinding="{Binding Location}"/>
</GridView>
</ListView.View>
</ListView>
Here is how I add Items to my ListView (results is a List of SearchFolder's):
results.Add(new SearchFolder { Name = Path.GetFileName(directory), Folder = Path.GetFileName(Path.GetDirectoryName(directory)), Location = directory });
resultsView.ItemsSource = results;
And my SearchFolder class
class SearchFolder
{
public string Name { get; set; }
public string Folder { get; set; }
public string Location { get; set; }
}
How do I create a ContextMenu, where the action (copy Path or open Folder) is executed on the clicked item in the ListView?
/edit: this way, the ContextMenu shows up no matter where I right click. But I can't find a way to access the clicked item, this does NOT WORK:
MenuItem temp = sender as MenuItem;
if (temp != null)
{
ContextMenu anotherTemp = temp.Parent as ContextMenu;
if (anotherTemp != null)
{
ListViewItem clickedItem = anotherTemp.PlacementTarget as ListViewItem;
if (clickedItem != null)
{
Console.WriteLine("Copy Path " + clickedItem.Name);
}
}
}
Upvotes: 1
Views: 2112
Reputation: 841
Try this on your click event handler:
private void ItemRightClick(object sender, EventArgs e)
{
MenuItem item = sender as MenuItem;
if (item!= null)
{
ContextMenu contextMenu = item.Parent;
Control clickedControl = contextMenu.SourceControl;
}
}
haven't checked it...
anyways, another way of doing it is using the 'MouseDown' event and checking if the button clicked was the right one:
private void ItemMouseDown(object sender, MouseEventArgs e)
{
if(e.Button == MouseButtons.Right)
{
ListViewItem item = listView.GetItemAt(e.X, e.Y);
if(item != null)
{
// here we have
}
}
}
Upvotes: 0
Reputation: 369
I finally managed to do what I wanted, I left the context menu as it was before and was able to get the item with the following code in the Event Handlers for the MenuItems in the ContextMenu
if(resultsView.SelectedIndex>-1)
{
SearchFolder selectedItem;
selectedItem = (SearchFolder)resultsView.SelectedItem;
//do stuff with selectedItem
}
Upvotes: 1
Reputation: 188
ListView have one event "SelectionChanged".Use this event you can set all your code in this event and access a item in sender.
Code:
<ListBox Grid.Row="1" Grid.Column="1" Margin="10,10,0,0" x:Name="lstBank" Style="{StaticResource TransparentListBox}" ItemTemplate="{StaticResource BankDataTemplate}"
MinHeight="35" MaxHeight="220" SelectionMode="Single" ItemsSource="{Binding Path=Banks}" ScrollViewer.HorizontalScrollBarVisibility="Disabled" SelectionChanged="lstBank_SelectionChanged" />
and set code in class file.
private void lstBank_SelectionChanged(object sender, System.Windows.Controls.SelectionChangedEventArgs e) {
}
Upvotes: 3