CODEWITHSUNDEEP
jquery
Gordon
Gordon

Reputation: 1651

jquery, cloning issue and keeping unique ids!

I decided to use jquery to create the duplicate of dropdown menus instead of using my perl script. I have come to an issue.

I have a series of drop boxes that I clone multiple times. The structure is like this:

<div id="org_dropmenus_asdf">
    <table border="0">
    <tr>
    <td valign="top">
        <select name="wimpy_asdf_1" id="wimpy_asdf_1" size="4">
          <option value='1'>1</option>
          <option value='2'>2</option>
        </select>;
    </td>
    <td valign="top">
        <select name="monkey_asdf_1" id="monkey_asdf_1" size="4">
          <option value='c'>c</option>
          <option value='d'>d</option>
        </select>;    
    </td>
            </tr>
            </table><p>
    </div>|;

I clone var $cloneDiv = $('#org_dropmenus_asdf').clone();

How can search and replace the asdf_1 ("1") and increment with new values?

Upvotes: 1

Views: 796

Answers (3)

phpboy
phpboy

Reputation: 11

Here's another way of overcoming this issue. I use the id and name in as an array so it make it easier to post to PHP and process without too much effort. This ties up two field names to I can link them when I post. it's a select and a text field. This happens after I've appended a clone.

var newid = Number($('.table_id').last().find(':text').attr('id').substr(-2,1)) + 1;

$('.table_id').last().find(':text').attr('id','detailValue['+newid+']').attr('name','detailValue['+newid+']');
$('.table_id').last().find(':select').attr('id','detailValue['+newid+']').attr('name','detailValue['+newid+']');

Upvotes: 1

karim79
karim79

Reputation: 342635

function incrementId(idString) {

    // split it at the underscore
    var pieces = idString.split("_");

    // if there is a fourth element, then it just needs incrementing
    if (pieces[3]) {
        pieces[3] = parseInt(pieces[3]) + 1;

    // if not, then it needs to be added
    } else {
        pieces[3] = "1";
    }

    // reconstruct the ID by joining with the underscore character
    return pieces.join("_");
}

$cloneDiv = $('#org_dropmenus_asdf').clone();

// get the ID of the last 'org_dropmenus_asdf' div and increment
var lastDivId = incrementId($("div[id^=org_dropmenus_asdf]:last").attr("id"));

// get the IDs of the contained select elements, and increment
var selectIds = $("div[id^=org_dropmenus_asdf]:last select").map(function() {
    return incrementId(this.id);
}).get();

alert(lastDivId);
alert(selectIds);

Partial demo + proof of concept: http://jsfiddle.net/karim79/fL9ve/2/

Upvotes: 1

lonesomeday
lonesomeday

Reputation: 237847

You need to do something along the lines of this:

var counter = 1;
$cloneDiv = $('#org_dropmenus_asdf').clone().find('[id]').attr('id', function(idx, oldId){
    return oldId.substr(0, -1) + counter;
}).attr('name', function (idx, oldName) {
    return oldName.substr(0, -1) + counter;
});

You could do this repeatedly, incrementing counter each time. Note that this code will only work up to 9, because it removes the last character; more characters need to be removed above 10.

Note also that this doesn't change the org_dropmenus_asdf id attribute, which also needs to be changed for a valid DOM.

Upvotes: 1

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