CODEWITHSUNDEEP
phpregex
JamesG
JamesG

Reputation: 1601

PHP Regex: Stop if exists or carry one

I am struggling to match for a phrase with an if char exists regex query. What I want to be able to do is scan this string:

teamplayerID=5432&groupplayerID=2345

and only get out teamplayerID=5432. Sometimes &groupplayerID exists and sometimes not.

I have tried:

/teamplayerID=(.*)(&?)/

over at https://regex101.com/r/QmMUkm/1

However that code above seems to select the entire string,

Question

How do I get the regex to stop if it detects an & and only get what I want but also select what I want even if no & exists.

Upvotes: 0

Views: 49

Answers (2)

Andreas
Andreas

Reputation: 23958

If Teamplayer is always a number you can use \d+

teamplayerID=(\d+)
https://regex101.com/r/xj1WNN/1

If it's not always a number you can use \w+ which will match both numbers and letters.

teamplayerID=(\w+)
https://regex101.com/r/xj1WNN/1


There is always a posibility for non regex. 

$str = "teamplayerID=54";

$pos1 = strpos($str, "=")+1;
$pos2 = strpos($str, "&", $pos1);
if($pos2 == 0) $pos2 = strlen($str);
echo substr($str, $pos1, $pos2-$pos1);

Find = save as pos1.
Find & after = and save as pos2.
If there is no & use strlen($str) as pos2.
Substring pos1 and lenght (pos2-pos1).

https://3v4l.org/7cj6J

EDIT; Forgot about the groupID not always being there.

Upvotes: 0

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626747

You need to use a [^&]* negated character class:

teamplayerID=([^&]*)

See the regex demo

The [^&]* pattern matches 0 or more occurrences of characters other than &.

If the ID is always a group of digits, just use \d* (0+ digits) instead, teamplayerID=(\d*).

Upvotes: 3

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