Reputation: 462
I want to take input from an HTML form and give the output in JSON format. When multiple values are selected they are not converted into JSON arrays, only the first value is used.
@app.route('/form')
def show_form():
return render_template('form.html')
@app.route("/result", methods=['POST'])
def show_result():
result = request.form
return render_template('result.html', result=result)
form.html
:
<form method=POST>
<input name=server>
<select name=owners multiple>
<option value="thor">thor</option>
<option value="loki">loki</option>
<option value="flash">flash</option>
<option value="batman">batman</option>
</select>
<input type=submit>
</form>
result.html
:
{{ result|tojson }}
When multiple values for owner are selected, "thor" and "flash", the output shows only one value:
{"server": "app-srv", "owners": "thor"}
I expect owners to be a list:
{"server": "app-srv", "owners": ["thor", "flash"]}
How do I display the form as JSON without losing list values?
Upvotes: 13
Views: 23295
Reputation: 1444
Difference in results when using the "flat" parameter:
result = request.form.to_dict(flat=True)
Result: {'a': '6', 'b': '7', 'c': '8'}
result = request.form.to_dict(flat=False)
Result: {'a': ['6'], 'b': ['7'], 'c': ['8']}
Upvotes: 0
Reputation: 127200
request.form
is a MultiDict
. Iterating over a multidict only returns the first value for each key. To get a dictionary with lists of values, use to_dict(flat=False)
.
result = request.form.to_dict(flat=False)
All values will be lists, even if there's only one item, for consistency. If you want to flatten single-value items, you need to process the data manually. Use iterlists
with a dict comprehension.
result = {
key: value[0] if len(value) == 1 else value
for key, value in request.form.iterlists()
}
Upvotes: 25