CODEWITHSUNDEEP
syntaxerlang
Code Wiget
Code Wiget

Reputation: 1682

Function with record as argument

I know this is very basic, but it's driving me up a wall:

peercert is defined as:

peercert(Socket) -> {ok, Cert} | {error, Reason}

Types

Socket = sslsocket()
Cert = binary()
The peer certificate is returned as a DER-encoded binary. The certificate can be decoded with public_key:pkix_decode_cert/2.

Ok, great. sslsocket is defined as -record(sslsocket, {fd = nil, pid = nil})

So I run :

New = #sslsocket{pid = Pid},
io:fwrite("~n~npeercert~p~n~n", [ssl:peercert(New)]).

But I get an error that 

no function clause matching ssl:peercert({sslsocket,<0.1277.0>,undefined})

So I run it with Pid as an argument and get a similar error:

no function clause matching ssl:peercert(<0.1277.0>)

I'm totally stumped here. I had it working before, the function says it takes these as arguments...

Thank you for your help in advance!

Upvotes: 0

Views: 58

Answers (1)

Tomasz Maciejewski
Tomasz Maciejewski

Reputation: 513

sslsocket() type is not a record called sslsocket, otherwise it would be written as #sslsocket{}. It's a "black box type" (its real type is an implementation detail), but you can obtain it from function ssl:connect().

Upvotes: 1

Related Questions