Reputation: 73
Lets assume n=20
so after every 6 iterations I will do some processing
int i=0
for (t=6;t<20;t=t+6){
while(i<=t){
will do some processing
i++;
}
}
In the above code it will terminate when t=18, but I want to continue until 20. How to do that ?
Upvotes: 0
Views: 76
Reputation: 1658
your code is not doing something every 6th iteration, but instead you are doing (n - n%6) times. your "will do some processing" is inside the while. If you add a print (or debug) there you will notice it; on the n=20 example the while will be executed 18 times; it will do something 18 times.
if you want to execute every 6th iterations, and include one extra for the cases that are not exactly divisible by 6, then you could do:
if (n == 0) {
return;
}
int number_iterations = n/6 + (n%6!=0 ? 1:0);
for (int i=0; i<number_iterations; i++) {
// do something
}
That covers what you requested; if not, pls edit question to be more clear on your exact needs.
Upvotes: 1
Reputation: 48297
You are increasing the t variable 6 units... the last condition that satisfies the t<20
is when t = 18
.
instead of doing t+=6
do a normal t++
and play with the modulo %6
example:
public static void main(String[] args) {
int n = 20;
for (int i = 0; i < n; i++) {
//TODDY
insert your while in here depending on when that must be executed
if (i % 6 == 0) {
System.out.println("am on a 6 modulo step..." + i);
} else {
System.out.println("foo@" + i);
}
}
System.out.println("done");
}
Upvotes: 2
Reputation: 2404
The behaviour is correct only.. Still if you want to perform any operation, do it after the condition is met, try below snippet:
int i = 0, n = 20;
do{
i += 6;
System.out.println(i);
} while (i < n);
System.out.println(i);
Upvotes: 1