shashantrika
shashantrika

Reputation: 1089

Getting the newly added , deleted , modified values in hashmap at a particular state

I have an application , which operates on the hashmap at stages , in the sense it adds/deletes/modifies keys in different classes . Thought of creating wrapper class by extending the Map class . And Hacking the predefined put and remove methods .

STAGE 1 :

HashMap<String, String> hashMap = new HashMap<>();
hashMap.put("Key1","Value1");
hashMap.put("Key2","Value2");
hashMap.put("Key3","Value3");
hashMap.put("Key4", "Value4");

Desired Result :
Added:
Key1 : Value1
Key2 : Value2
Key3 : Value3
Key4 : Value4

STAGE 2:

hashMap.remove("Key1");

Desired Result :
Removed:
Key1 : Value1

STAGE 3:

hashMap.put("Key2", "ChangedValue");

Desired Result :
Modified :
Key2 : ChangedValue

What would be the best way or best logic to get only the diff ? The dataStructure HASHMAP is fixed .

Upvotes: 1

Views: 339

Answers (1)

Assafs
Assafs

Reputation: 3275

The simplest way is to extend HashMap to your own class, and record the changes:

class RecordHashMap extends HashMap<String,String> {
    private List<String[]> changes;

    public RecordHashMap() {
      super();
      changes = new ArrayList<String[]>();
    }

    @Override
    public String put(String key, String value) {

        if (containsKey(key)) {
            changes.add(new String[]{"modified",key,value});
        } else {
            changes.add(new String[]{"added",key,value});
        }
        return super.put(key, value);
     }

     @Override
     public String remove(Object key) {
         if (containsKey(key)) {
             String value = get(key);
             changes.add (new String[]{"removed",(String)key,value});
         }
         return super.remove(key);
     }

     public List<String[]> getChanges() {

         return changes;
    }
}

This way you can always check the last change, as they are all recorded. You can of course print them out as you record them - or later. You can add an index counter (to allow to only look at x recent changes), since you store them in an array list.

Upvotes: 1

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