CODEWITHSUNDEEP
c++
wang
wang

Reputation: 55

how can I check argument size in class constructor in c++

for example:

class Static {
public:
    Static(std::vector<int> v) {
        if (v.size() ! = 3) {
            //...
        }
    }
    ~Static() {
        std::cout << "Static dtor\n";
    }
};

I have class named Static, and its constructor has a argument v, how can I check v'size, and if v.size() < 3, the constructor exit

many answers say that it can be solved by using throw a exception, but the problem is that the destructor will not be call.

so I wonder whether return will be ok, for examples:

class Static {
public:
    Static(std::vector<int> v) {
        if (v.size() ! = 3) {
            //to log some error info
            return;
        }
    }
    ~Static() {
        std::cout << "Static dtor\n";
    }
};

Upvotes: 1

Views: 80

Answers (1)

user0042
user0042

Reputation: 8018

so I wonder whether return will be ok, for examples:

Most probably that's not OK, because it leaves you with a Static instance in an invalid and improperly initialized state.

The only way to avoid that, and keep everything clean is throwing an exception.

Assumed you want to manage a std:.vector<int> with a fixed size of 3 internally, it would be better to rewrite your constructor like

Static(int a, int b, int c) {
    v_.push_back(a);
    v_.push_back(b);
    v_.push_back(c);
}

Upvotes: 1

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