CODEWITHSUNDEEP
r
Hadsga
Hadsga

Reputation: 333

mean in R: argument is not numeric

I'm trying to replace the values of a column with NA with the mean of the column.

I already tried the following solutions:

titanic3$age[which(is.na(titanic3$age))] <- mean(titanic3$age, use = 
"complete.obs") 
titanic3$age[which(is.na(titanic3$age))] <- mean(titanic3[,age], use = 
"complete.obs")
titanic3$age[which(is.na(titanic3$age))] <- mean(titanic3[[age]], use = 
"complete.obs")

But it didn´t work. Any ideas?

Upvotes: 0

Views: 128

Answers (2)

akrun
akrun

Reputation: 887158

We can do this easily with na.aggregate

library(zoo)
titanic3$age <- na.aggregate(titanic3$age)

By default, the FUN would be mean to replace the NA values with the mean of that column

Upvotes: 2

moodymudskipper
moodymudskipper

Reputation: 47320

Try this :

titanic3$age[is.na(titanic3$age)] <- mean(titanic3$age, na.rm = T)

Upvotes: 0

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