CODEWITHSUNDEEP
javascriptrequirejs
nicholaswmin
nicholaswmin

Reputation: 22939

Bundling a bunch of require statements while avoiding namespacing

I've got a test suite and in each test file I find myself commonly importing a bunch of modules

const chai = require('chai')
const sinon = require('sinon')
const expect = chai.expect
const should = chai.should()
const testData = require('../test/test-data')

Is there any way to bundle all those require calls in one require, without using a namespace?

E.g something like this:

require('../test/test-bundle')

console.log(chai) // ok
console.log(sinon) // ok
console.log(expect) // ok
console.log(should) // ok
console.log(testData) // ok

Upvotes: 2

Views: 65

Answers (1)

alexmac
alexmac

Reputation: 19587

I can not say that my solution is very good, but it will allow you to reduce the number of duplicate code. You could define a new module (test-util.js) and require all needed modules there. After that, in each test, require only one module and use destructuring assignment syntax to avoid namespace.

The destructuring assignment syntax is a JavaScript expression that makes it possible to unpack values from arrays, or properties from objects, into distinct variables.

test-util.js:

module.exports = {
  chai: require('chai'),
  sinon: require('sinon'),
  expect: require('chai').expect,
  should: require('chai').should(),
  testData: require('../test/test-data')
};

test.js

let { chai, sinon, expect, should, testData } = require('./test-util.js');

Upvotes: 2

Related Questions