CODEWITHSUNDEEP
androidjsongsonretrofit
Polam Naganji
Polam Naganji

Reputation: 287

How to handle JSON data which has = and : characters in json value in Android

Below is the JSON response I am getting for API requests.

user = { 'name':'Siva', 'address':'my address', 'pincode':12345, 'url':'http://myweb.com/index.php?title=firstname:lastname+middlename&action=edit' }

As this JSON response started with user = its neither JSONObject nor JSONArray. So I considered this as String and i split the response

String[] response = responseBody.split("=");

Gson gson = new GsonBuilder().setLenient().create();

User user = gson.fromJson(response[1], User.class);

This is causing MalformedJsonException like below

Caused by: com.google.gson.stream.MalformedJsonException: Unterminated string at line 5 column 47 path $.url

I observed that value for url key is causing issues. Because it has = and : characters in url value. But i did not find the proper solution.

Can anybody help me on how to handle this.

Upvotes: 1

Views: 125

Answers (2)

fluffyBatman
fluffyBatman

Reputation: 6704

After you get this in response[1],

{ 'name':'Siva', 'address':'my address', 'pincode':12345, 'url':'http://myweb.com/index.php?title=firstname:lastname+middlename&action=edit' }

replace the ' with " first. Like this,

response[1] = response[1].replaceAll("\'", "\"");

Check the response after that to be sure that all the ' are actually replaced by ".

Then see if it parses afterwards.

Upvotes: 0

Sajidh Zahir
Sajidh Zahir

Reputation: 526

Since you have been using gson could do something like this 

    Gson g = new Gson();

Person person = g.fromJson(responsejsonstring, Person.class);
System.out.println(person.name); //[email protected]

System.out.println(g.toJson(person)); // {"email":"[email protected]"}

Upvotes: 1

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