Reputation: 524
I use this code to get a specific field in php
$client = new MongoDB\Client("mongodb://localhost:27017");
$collection = $client->test->users;
$result = $collection->find(array(), array('name' => 1, '_id' => 1));
But it returns all fields.
I get the last line from this link:
http://php.net/manual/en/mongo.sqltomongo.php
Data:
object(MongoDB\Model\BSONDocument)#36 (1) { ["storage":"ArrayObject":private]=> array(7) { ["_id"]=> object(MongoDB\BSON\ObjectID)#35 (1) { ["oid"]=> string(24) "598ebdeab318de646ca08788" } ["is_hidden"]=> bool(false) ["priority"]=> int(1) ["picture"]=> string(21) "15025269499885875.jpg" ["__v"]=> int(0) ["name"]=> string(8) "John" } }
Expected result:
object(MongoDB\Model\BSONDocument)#36 (1) { ["storage":"ArrayObject":private]=> array(7) { ["_id"]=> object(MongoDB\BSON\ObjectID)#35 (1) { ["oid"]=> string(24) "598ebdeab318de646ca08788" } ["name"]=> string(8) "John" } }
Upvotes: 6
Views: 5961
Reputation: 524
(Solved):
Last line should be this:
$result = $collection->find(array(), array('projection' => array('name' => 1, '_id' => 1)));
Upvotes: 10