CODEWITHSUNDEEP
pythondictionarytext
Tom
Tom

Reputation: 3

Creating a Dictionary from txt

I have a couple of lines inside a text that i am looking to turn the first word to a key (space is between each) with a function, and the rest to follow as values. This is what the text contains:

FFFB10 11290 Charlie
1A9345 37659 Delta
221002 93323 Omega

The idea is to turn the first word into a key, but also arrange it (row underneath a row) visualy, so the first word(FFFB10) is the key, and the rest are values, meaning:

Entered: FFFB10
Location: 11290
Name: Charlie

I tried with this as a beginning:

def code(codeenter, file):
  for line in file.splitlines():
    if name in line:
        parts = line.split(' ')

But i dont know how to continue (i erased most of the code), any suggestions?

Upvotes: 0

Views: 58

Answers (4)

ForceBru
ForceBru

Reputation: 44828

Assuming you managed to extract a list of lines without the newline character at the end.

def MakeDict(lines):
    return {key: (location, name) for key, location, name in (line.split() for line in lines)}

This is an ordinary dictionary comprehension with a generator expression. The former is all the stuff in brackets and the latter is inside the last pair of brackets. line.split splits a line with whitespace being the delimiter.

Example run:

>>> data = '''FFFB10 11290 Charlie
... 1A9345 37659 Delta
... 221002 93323 Omega'''
>>> lines = data.split('\n')
>>> lines
['FFFB10 11290 Charlie', '1A9345 37659 Delta', '221002 93323 Omega']
>>> def MakeDict(lines):
...   return {key: (location, name) for key, location, name in (line.split() for line in lines)}
...   
>>> 
>>> MakeDict(lines)
{'FFFB10': ('11290', 'Charlie'), '1A9345': ('37659', 'Delta'), '221002': ('93323', 'Omega')}

How to format the output:

for key, values in MakeDict(lines).items():
    print("Key: {}\nLocation: {}\nName: {}".format(key, *values))

Upvotes: 4

Alexander
Alexander

Reputation: 109510

You may want to consider using namedtuple.

from collections import namedtuple

code = {}
Code = namedtuple('Code', 'Entered Location Name')
filename = '/Users/ca_mini/Downloads/junk.txt'
with open(filename, 'r') as f:
    for row in f:
        row = row.split()
        code[row[0]] = Code(*row)
>>> code
{'1A9345': Code(Entered='1A9345', Location='37659', Name='Delta'),
 '221002': Code(Entered='221002', Location='93323', Name='Omega'),
 'FFFB10': Code(Entered='FFFB10', Location='11290', Name='Charlie')}

Upvotes: 0

Ajax1234
Ajax1234

Reputation: 71451

You can try this:

f = [i.strip('\n').split() for i in open('filename.txt')]

final_dict = {i[0]:i[1:] for i in f}

Assuming the data is structured like this:

FFFB10 11290 Charlie
1A9345 37659 Delta
221002 93323 Omega

Your output will be:

{'FFFB10': ['11290', 'Charlie'], '221002': ['93323', 'Omega'], '1A9345': ['37659', 'Delta']}

Upvotes: 0

DYZ
DYZ

Reputation: 57033

See ForceBru's answer on how to construct the dictionary. Here's the printing part:

for k, (v1, v2) in your_dict.items():
    print("Entered: {}\nLocation: {}\nName: {}\n".format(k, v1, v2))

Upvotes: 0

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