CODEWITHSUNDEEP
c++
q0987
q0987

Reputation: 35992

C++ -- What is the meaning of this statement?

I saw the following class definition and cannot figure out the meaning of the line 1.

class Noisy {
public:
  Noisy() throw();
 ~Noisy() throw();
  Noisy& operator= (const Noisy&) throw();
  Noisy            (const Noisy&) throw(); // Line 1
};

What is the meaning of this line and what is the usage of this line?

Thank you

Upvotes: 0

Views: 183

Answers (2)

santiagoIT
santiagoIT

Reputation: 9431

Look at this thread. It will give you some more insight. Should I use an exception specifier in C++?

Upvotes: 0

James McNellis
James McNellis

Reputation: 355297

It isn't a statement. It is a declaration of a copy constructor that is specified as throwing no exceptions.

You can find out more in your favorite good introductory C++ book.

Upvotes: 7

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