Reputation: 223
Function of insertion sort is not working, Error is : A function is taking too long to run. Perhaps you have a mistake in your code?
// this function
var insert = function(array, rightIndex, value) {
for(var j = rightIndex;
j >= 0 && array[j] > value;
j--)
{
array[j + 1] = array[j];
}
array[j + 1] = value;
};
var insertionSort = function(array) {
for(var i = 0; i < array.length ; i++)
{
insert(array,i,array[i+1]);
}
};
var array = [22, 11, 99, 88, 9, 7, 42];
insertionSort(array);
println("Array after sorting: " + array);
Program.assertEqual(array, [7, 9, 11, 22, 42, 88, 99]);
Upvotes: 0
Views: 61
Reputation: 43
Try going through the array backwards inside the insertionSort function:
var insertionSort = function(array) {
for (var i = array.length - 1; i >= 0; i--) {
insert(array,i,array[i+1]);
}
};
Upvotes: 0
Reputation:
Your problem is on choosing array position as [i+1]
and [j+1]
change
var insert = function(array, rightIndex, value) {
for(var j = rightIndex;
j >= 0 && array[j] > value;
j--)
{
array[j + 1] = array[j];
}
array[j + 1] = value;
};
into
var insert = function(array, rightIndex, value) {
for(var j = rightIndex;
j > 0 && array[j-1] > value;
j--)
{
array[j] = array[j-1];
}
array[j] = value;
};
and
insert(array, i, array[i+1]);
into
insert(array, i, array[i]);
Upvotes: 1
Reputation: 2327
var insert = function(array, rightIndex, value) {
for(var j = rightIndex;
j >= 0 && array[j] > value;
j--)
{
array[j + 1] = array[j];
}
array[j + 1] = value;
};
var insertionSort = function(array) {
for(var i = 0; i < array.length - 1 ; i++)
{
insert(array,i,array[i+1]);
}
};
var array = [22, 11, 99, 88, 9, 7, 42];
insertionSort(array);
console.log(array);
you should run your loop 1 less iteration as you are calling the insert() function with i + 1;
Upvotes: 0