Reputation: 155
I have this table:
Year Month| User| Player | Manager
1996-06 | 1256| 2 | 1
1997-07 | 1243| 5 | 2
and was trying to pivot it so it returns:
| 1997-06|1996-07
User | 1256 | 1243
Player | 2 | 5
Manager| 1 | 2
however I'm not to sure why my script below is returning something different:
DECLARE @columns NVARCHAR(MAX), @sql NVARCHAR(MAX);
SET @columns = N'';
SELECT @columns += N', p.' + QUOTENAME([User])
FROM (SELECT p.[User] FROM dbo.practise AS p
GROUP BY p.[User]) AS x;
SET @sql = N'
SELECT ' + STUFF(@columns, 1, 2, '') + '
FROM
(
SELECT [year month], [User]
FROM dbo.practise AS p
) AS j
PIVOT
(
SUM([User]) FOR [year month] IN ('
+ STUFF(REPLACE(@columns, ', p.[', ',['), 1, 1, '')
+ ')
) AS p;';
PRINT @sql;
EXEC sp_executesql @sql;
It returns:
1256|1243
1 Null|Null
Not sure what I'm doing wrong :/
Upvotes: 3
Views: 92
Reputation: 81990
Your could simplify this a bit
Example
Declare @SQL varchar(max) = '
Select *
From (
Select [Year Month]
,B.*
From practise
Cross Apply (values (''User'' ,cast([User] as varchar(max)))
,(''Player'' ,cast(Player as varchar(max)))
,(''Manager'',cast(Manager as varchar(max)))
) B (Item,Value)
) A
Pivot (max([Value]) For [year month] in (' + Stuff((Select Distinct ','+QuoteName([year month])
From practise
Order By 1
For XML Path('')),1,1,'') + ') ) p
Order by 1 Desc'
Exec(@SQL);
--Print @SQL
Returns
Item 1996-06 1997-07
User 1256 1243
Player 2 5
Manager 1 2
The Generated SQL Looks Like This
Select *
From (
Select [Year Month]
,B.*
From practise
Cross Apply (values ('User' ,cast([User] as varchar(max)))
,('Player' ,cast(Player as varchar(max)))
,('Manager',cast(Manager as varchar(max)))
) B (Item,Value)
) A
Pivot (max([Value]) For [year month] in ([1996-06],[1997-07]) ) p
Order by 1 Desc
Upvotes: 1